We have to add the both half cell equations and eliminate the number of electrons lost/gained.
<h3>What modification must Kim make to the equations?</h3>
The term redox reaction is a type of reaction that occurs when an electron is lost or gained in a reaction system. We can see that in this reaction, zinc looses two electron which are gained by copper.
If we want to obtain the equation 4.9 which is the overall equation of the redox reaction from the various half cell equations then we have to add the both half cell equations and eliminate the number of electrons lost/gained.
Learn kore about redox reaction:brainly.com/question/13293425
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Answer:
C. gravity causing a curved path as an object tries to go straight.
Hydroxylamine in water: HONH₂(aq) + H₂O(l) ⇄ HONH₃⁺(aq) + OH⁻(aq).
Hydroxylammonium nitrate in water: HONH₃NO₃(aq) → OHNH₃⁺(aq) + NO₃⁻(aq).
1) with positive hydrogen ions (protons) react base and gives weak conjugate acid:
H⁺(aq) + HONH₂(aq) ⇄ HONH₃⁺(aq).
2) with hydroxide anions react acid and produce weak base and weak electrolyte water:
HONH₃⁺(aq) + OH⁻(aq) ⇄ HONH₂(aq) + H₂O(l).
b or d
Explanation:
I think it's either b or d sorry if I'm wrong
To convert the given value we need conversion factors to relate molecules to liters. At STP, we know that 1 mol is equal to 22.4 L and by using Avogadro's number we can relate molecules to 1 mol. Calculation is as follows:
5.0x10^24 molecules ( 1
mol / <span>6.022 x 10^23 molecules<span> ) ( 22.4 L / 1 mol) = 186.0 L </span></span>
