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lapo4ka [179]
2 years ago
12

How to light a candle without touching it?​

Chemistry
2 answers:
nignag [31]2 years ago
6 0
Just don’t touch it-

it’s not that hard
vlabodo [156]2 years ago
4 0

Answer:

use a lighter

Explanation:

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Low melting point and poor conductor of electricity
WINSTONCH [101]

i THINK THE ANSWER IS A

5 0
3 years ago
A chemistry student needs to standardize a fresh solution of sodium hydroxide. She carefully weighs out 192.mg of oxalic acid H2
kap26 [50]

Answer:

The molarity of the NaOH solution is 0.076 M

Explanation:

Step 1: Data given

Mass of oxalic acid = 192 mg = 0.192 grams

volume = 250 mL = 0.250 L

Molar mass oxalic acid = 90.03 g/mol

Step 2: The balanced equation

H2C2O4 + 2NaOH → Na2C2O4 + H2O

Step 3: Calculate moles of oxalic acid

Moles oxalic acid = 0.192 grams / 90.03 g/mol

Moles oxalic acid = 0.00213 moles

Step 4: Calculate molarity of oxalic acid

Molarity = Moles / volume

Molarity = 0.00213 moles / 0.250 L

Molarity = 0.00852 M

Step 5: Calculate Molarity of NaOH

2 Ca*Va = Cb*Vb

with Ca = Molarity of oxalic acid = 0.00852 M

with Va = volume of oxalic acid = 0.250 L

with Cb = Molarity of NaOH = TO BE DETERMINED

with Vb = volume of 0.0558 L

Cb = (2*0.00852 * 0.25) / 0.0558

Cb = 0.076 M

The molarity of the NaOH solution is 0.076 M

4 0
3 years ago
What is the percentage of sodium presents in sodium hydrogen carbonate NaHCO3
STatiana [176]

Answer:-

27.38%

Explanation:-

Molecular weight of sodium hydrogen carbonate NaHCO3

= 23 x 1 + 1 x 1 + 12 x 1 + 16 x 3

= 84 gram

Total sodium Na present in NaHCO3 = 23 x 1 = 23 gram

Percentage of sodium present=

Total sodium x 100/ (Total molecular weight)

= 23 x 100 / 84

= 27.38 %

3 0
2 years ago
Oxygen is produced at the positive electrode
abruzzese [7]

Answer:

See Explanation

Explanation:

In electrolysis, a solution called the electrolyte is decomposed by the passage of direct current through it.

The points through which current enters and leaves the electrolyte are called electrodes. In electrolysis, oxidation occurs at the anode and reduction occurs at the cathode.

In the electrolysis of water; at the anode oxygen is produced as follows;

4OH^-(aq) -----> 2H2O(l) + O2(g) + 4e

5 0
3 years ago
How do we balance a chemical equation 4 marks?.
Vesna [10]

To balance a chemical equation, place coefficient as needed in front of the symbols or formulas of the elements. So the same number of each type of atom occurs in both reactants and products.

Steps to be followed are-

(1) Write down the chemical reaction in the form of word equation, keeping all the reactants on left hand side and keeping products on right hand side.

(2) Write all the symbol and formula of all reactants and products in word equation.

(3) Balance the whole equation by multiplying the symbols and formula by smallest possible figures.

Same number of each and every atom, of same type occurs in both reactants and products.

Once all the individual elements are balanced, then the total number of atoms of each element on the reactant and product side are compared once again after balancing. If there are no inequalities, the chemical equation is said to be balanced.

To learn more about balancing chemical equations visit the link- brainly.com/question/26227625

#SPJ4

6 0
1 year ago
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