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The given question is incomplete. The complete question is:
Calculate the number of moles and the mass of the solute in each of the following solution: 100.0 mL of 3.8 × 10−5 M NaCN, the minimum lethal concentration of sodium cyanide in blood serum
Answer: The number of moles and the mass of the solute are and
respectively
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.
where,
n = moles of solute
= volume of solution in ml
n = moles of =
Thus the number of moles and the mass of the solute are and
respectively
75 g of sodium hydroxide is present in the solution.
<u> </u><u>Explanation</u><u> :</u>
Given :
Molarity of sodium hydroxide solution= 2.5 M
Litres of Solution = 750 mL
Molar mass of NaOH = 40 g/mol
To Find:
Grams of Sodium Hydroxide =?
Solution :
Molarity of the solution is expressed in Litres, So Converting 750.0 mL to Litres we have
750.0mL=0.750 Litres
Grams of Solution
, moles=
Where
M = Molarity
L = litres of solution
mol= moles of solute
Mol = 1.875
Also the molecular weight of NaOH is 40.00 g/mol
Grams of sodium hydroxide = 1.875 mol * 40.00 g/mol = 75 g