Answer:
80.0 g Na and 20.0 g N2.
Explanation:
This means the limiting reactant determines the maximum mass of the product formed.
Answer:
1.58×10E18
Explanation:
Since we have the reduction potentials we could make decisions regarding which one will be the anode or cathode. Evidently, bromine having the more positive reduction potential will be the cathode while the iodine will be the anode.
E°cell= 1.07- 0.53= 0.54 V
E°cell= 0.0592/n logK
0.54 = 0.0592/2 logK
logK= 0.54/0.0296
logK= 18.2
K= Antilog (18.2)
K= 1.58×10^18
Answer: if I’m not mistaken it would be 8
Explanation:
Answer:
The right choice is → a reduction reaction
Explanation:
From the balanced equation
- 3CIO⁻₍aq₎ → CIO⁻ ₍aq₎ + 2Cl⁻ ₍aq₎
we can calculate the change in oxidation number of Cl in reactant and product
in reactant ClO⁻
let x= oxidation number of Cl
and oxidation number of oxygen in its compound is (-2)
and the total charge on the ClO⁻ ion = -1
- ∴x + (-2) = -1 →→→ x = +1
in product Cl⁻
let x= oxidation number of Cl
and the total charge on the Cl⁻ ion = -1
so the oxidation number of Cl decreases from +1 in reactant to -1 in product so it is reduction reaction.
But, disproportionation reaction is defined as the chemical reaction in which a single substance gets reduced as well as oxidized.
For a disproportionated substance , it should contain at least three oxidation states. which isn't the case here.
<u>So, the right choice is: </u>
→ a reduction reaction
