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butalik [34]
3 years ago
11

Which term names the concentration of salts dissolved in a liquid?

Chemistry
2 answers:
Zanzabum3 years ago
7 0
Salinity because if u break the word down u get salt.
Viefleur [7K]3 years ago
4 0
Hey there!
The answer is D, Salinity.
Salinity is the concentration of salt in water. Ocean water often has high salinity and this can contribute to things like upwelling and water density- but these all start from salinity.
Hope this helps!
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LenaWriter [7]

Answer:

0.1139952 is the answer

Explanation:

4 0
3 years ago
Jason is preparing curry from an Indian cookbook his British brother-in-law gee him for his birthday. Unfortunately, the British
Marina CMI [18]

Answer:

0.99 pounds

2,000 oz

0.423 cups

Explanation:

In order  to convert this units we need to look up their equivalences.

1 g equals 0,0022 pounds approximately

Then we need to cross-multiply:

\frac{1 g}{0.0022 pounds} = \frac{450 g}{ Xpounds} \\x = \frac{450 g x 0.0022 pounds}{1 g}

450 g equals 0.99 pounds approximately

We can do the same calculation for the other 2 ingredients

1 g equals 16 oz

Then (125 g x 16 oz) / 1 oz = 2,000 oz  (or 500 4 oz)

1 cup equals 236.59 ml

Then (100 ml x 1 cup)/ 236.59 = 0.423 cups

6 0
3 years ago
Land is a natural resource because it is used by living things to meet their needs. O True
blondinia [14]

Answer:

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7 0
3 years ago
A chemical change occurs when select one:
Ne4ueva [31]
I think it is d. Because the process is not reversible and it a chemical process
7 0
3 years ago
2) If I have an unknown quantity (# of moles) of gas at a pressure of 32 atm, a volume of 70 L, and a temperature of 25˚C. How m
astra-53 [7]

Answer:

91.5 mol

Explanation:

Volume of gas = 70 L

Temperature = 25°C

Pressure = 32 atm

Moles of gas  = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Now we will convert the temperature.

25+273.15 = 298.15 K

By putting values,

32 atm × 70 L = n ×0.0821 atm.L /mol.K × 298.15 K

2240 atm.L = n ×24.48 atm.L /mol

n = 2240 atm.L / 24.48  atm.L /mol  

n = 91.5 mol

3 0
3 years ago
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