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DENIUS [597]
3 years ago
12

How to calculate the total current of a circuit which has both parallel and series connection

Physics
1 answer:
tankabanditka [31]3 years ago
3 0


1) using kirchhoff voltage and current law.
2) voltage and current divider rule
3) ohm's law
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El valor más preciso de la masa de un electron es 9.11*10^-11kg ¿ Cuánto aumentaría la masa de un cuerpo que se carga con -1 c d
chubhunter [2.5K]

Answer:

m = 569.375\times 10^{6}\,kg

Explanation:

Un electrón tiene una carga negativa de 1.6\times 10^{-19}\,C y la masa total es igual al producto del número de electrones y esa carga unitaria. El número de electrones se obtiene al dividir la carga total por la carga unitaria. (An electron has a negative charge of 1.6\times 10^{-19}\,C and the total mass is equal to the product of the qunatity of electrons and such unit charge. The quantity of electrons is found by diving the total charge by the unit charge):

m = \frac{Q}{q} \cdot m_{e}

m = \left(\frac{1\,C}{1.6\times 10^{-19}\,C} \right)\cdot (9.11\times 10^{-11}\,kg)

m = 569.375\times 10^{6}\,kg

7 0
4 years ago
Electrostatics is described as the study of electric charges that can be collected and held in place. Is this true or false?
Rasek [7]

Electrostatics is described as the study of electric charges that can be collected and held in place.

The above given statement is a true st

7 0
1 year ago
To which layer can geologists apply the principle of faunal succession to determine the age of the layer?
BigorU [14]
A. Layer C is the right answer out of all the choices
5 0
4 years ago
The time period T of a simple pendulum is given by the relation
Vanyuwa [196]

Answer:

T^2 \propto L

Explanation:

The period of a simple pendulum is given by:

T=2\pi \sqrt{\frac{L}{g}}

where

L is the length of the pendulum

g is the acceleration of gravity

From this equation we can write

T\propto \sqrt{L}\\T\propto \frac{1}{\sqrt{g}}

Taking the square of this equation, we get:

T^2 = (2\pi)^2 \frac{L}{g}

So we see that T^2 is proportional to L and inversely proportional to g. So, we can write:

T^2 \propto L\\T^2 \propto \frac{1}{g}

So the only correct option is

T^2 \propto L

5 0
4 years ago
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ASAP will mark brainlyist
Llana [10]

Answer:

315meters

Explanation:

Solution is attached.

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3 years ago
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