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rodikova [14]
3 years ago
12

Which measurement is a potential difference?

Physics
1 answer:
balu736 [363]3 years ago
4 0

Answer:

Potential difference (V) – is measured in volts (V).

A potential difference of 1 V means that 1 joule of work is done per coulomb of charge. ( 1 V = 1 J C-1) Potential difference in a circuit is measured using a voltmeter which is placed in parallel with the component of interest in the circuit.

Explanation:

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The colors you see during a sunset are caused by _____. the refraction of light by the atmosphere the absorption of light by the
love history [14]

Answer: the refraction of light by the atmosphere

Explanation: Refraction is the phenomenon in which there is a change in direction of light passing from one medium to another or from a gradual change in the medium.

Here in case of sunset, the sun rays passes through the varying density of atmosphere because of varying concentrations of dust particles.

Reflection is the phenomenon in which the light bounces back after falling on a surface.

Absorption is the phenomenon in which matter captures the electromagnetic radiations and thus the energy of photons is converted to internal energy of the system.

6 0
3 years ago
You hold a metal block of mass 40 kg above your head at a height of 2 m.
Kitty [74]

Answer:

The work done by gravity is 784 J.

Explanation:

Given:

Mass of the block is, m=40\ kg

Height to which it is raised is, h=2\ m

Acceleration due to gravity is, g=9.8\ m/s^2

Now, work done by gravity is equal to the product of force of gravity and the distance moved in the direction of gravity. So,

\textrm{Work by gravity}=F_g\times h

Force of gravity is given as the product of mass and acceleration due to gravity.

\therefore F_g=mg=40\times 9.8=392\ N. Now,

\textrm{Work by gravity}=F_g\times h=392\times 2=784\ J

Therefore, the work done by gravity is 784 J.

5 0
3 years ago
In the diagram, q1 = +6.60*10^-9 C and q2 = +3.10*10^-9 C. Find the magnitude of the total electric field at point P. pls help?
kirza4 [7]

Answer:

|E(t)| = 1258,46 [N/C]

α = 67,5⁰  (angle with respect x-axis)

Explanation:

E(t)  Electric Field is a vector, so we need to determine module and direction

E(t)  =  E(q₁)  + E (q₂)  Where E(q₁) and E (q₂) are electric fields due to electric charge q₁ and q₂  respectively.

E(q₁) = K * q₁/ (d₁)²         K = 9 *10⁹   [N*m²/C²]    d₁ = 0,350 m

E(q₁) = 9 *10⁹ * 6,6*10⁻⁹ / 0,1225      [N*m²/C²] *C/m²

E(q₁) = 484,9 [N/C]

E(q₂) =  9 *10⁹ * 3,1*10⁻⁹ / 0,024025

E(q₂) = 1161,29

Then

|E(t)| = √ |Eq₁|² + |Eq₂|²

|E(t)| = √ ( 484,9)² +( 1161,29)²

|E(t)| = √ 235128 + 1348594,46

|E(t)| = 1258,46 [N/C]

And tanα = 1161,29/484,9        tanα =  2,395      α = 67,5⁰

The angle of the vector electric field with the x-axis

3 0
3 years ago
Read 2 more answers
Temos os meios A e B. A luz no meio B com ângulo de incidência de 45º e n=V2, para o meio A com n=V3.
Neko [114]
A) o angulo de refracao
4 0
2 years ago
An iguana runs back and forth along the ground. The horizontal position of the iguana in meters over time is shown
pochemuha

Answer:

MY

7-

Col

6-

SA

5+

4-

MY

Pro

3

Pro

2

Tea

+

→ t(s)

1

2

3

4

5

6

7

3 0
2 years ago
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