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lukranit [14]
3 years ago
13

A car is traveling at 20 meters/second and is brought to rest by applying brakes over a period of 4 seconds. What is its average

acceleration over this time interval?
Physics
2 answers:
frez [133]3 years ago
8 0
 (u) = 20 m/s 
(v) = 0 m/s 
<span> (t) = 4 s 
</span>
<span>0 = 20 + a(4) 

</span><span>4 x a = -20 
</span>
so, the answer is <span>-5 m/s^2. or -5 meter per second</span>
Feliz [49]3 years ago
8 0
The answer is -5 m/s^2. or -5 meter per second
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Answer:

The value is v_2 =  5.53 \  m /s

Explanation:

From the question we are told

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Generally the area at location 1 is  

       A_1 =  \pi *  \frac{d^2}{ 2}

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=>     A_1 = 3.142 *  \frac{0.88^2}{ 2}

=>     A_1 = 1.2166 \  m^2

Generally the area at location 1 is  

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=>     A_2 =  \pi *  \frac{0.58^2}{ 2}

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Generally from continuity equation we have that

     A_1 * v_1 =  A_2 * v_2

=>   1.2166 *   2.4   =  0.528   * v_2

=>   1.2166 *   2.4   =  0.528   * v_2

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Answer:

100 miles North East.

Explanation:

Please see attached photo for diagram.

In the attached photo, X represents the magnitude of the total displacement of the train.

Thus, we can obtain the value of X by using the pythagoras theory as illustrated below:

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This will help you.

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