Ask question

Ask question

All categories

stepladder [879]

3 years ago

7

Can Someone help me ASAP please and thx

2 answers:

Tanya [424]3 years ago

5 0

It could be rock music because of his face expresion

BartSMP [9]3 years ago

4 0

Answer:

could be rock or maybe hip pop/ pop

Explanation:

You might be interested in

The Earth's gravity keeps us from flying out to space. How can you explain that we have a stronger gravitational attraction to t

julia-pushkina [17]

It's the fourth choice.

This is because, since we are closer to the Earth, the Earth will have a stronger gravitational pull on us since again, we are closer.
That also explains tides, but that's just getting off topic. Hope I helped.

6 0

3 years ago

Read 2 more answers

g determine what frequency is required of a source powering a 100 uf capacitor a 500 ohm resistor and a s50 mH inductor in serie

polet [3.4K]

Answer: $71.16\ Hz$

Explanation:

Given

Capacitance $C=100\ \mu F$

Resistance $R=500\ \Omega$

Inductance $L=50\ mH$

In LCR circuit, current is maximum at resonance frequency i.e.

$X_L=X_C\ \text{and}\ \omega_o=\dfrac{1}{\sqrt{LC}}$

Insert the values

$\Rightarrow \omega_o=\dfrac{1}{\sqrt{50\times 10^{-3}\times 100\times 10^{-6}}}\\\\\Rightarrow \omega_o=\dfrac{1}{\sqrt{5}\times 10^{-3}}\\\\\Rightarrow \omega_o=0.447\times 10^{3}$

Also, frequency is given by

$\Rightarrow 2\pi f=\omega_o\\\\\Rightarrow f=\frac{\omega_o}{2\pi}$

$\Rightarrow f=\dfrac{1}{2\pi}\times 0.447\times 10^3\\\\\Rightarrow f=71.16\ Hz$

8 0

3 years ago

A cylinder is fitted with a piston, beneath which is a spring, as in the drawing. The cylinder is open to the air at the top. Fr

astraxan [27]

Answer:

x = 0.0734 m = 7.34 cm

Explanation:

First we shall calculate the area of the piston:

$Area = \pi radius^2\\Area = \pi (0.028\ m)^2\\Area = 0.00246\ m^2$

Now, we will calculate the force on the piston due to atmospheric pressure:

$Atmospheric\ Pressure = \frac{Force}{Area}\\\\Force = (Atmospheric\ Pressure)(Area)\\Force = (101325\ N/m^2)(0.00246\ m^2) \\Force = F = 249.56\ N$

Now, for the compression of the spring we will use Hooke's Law as follows:

$F = kx\\$

where,

k = spring constant = 3400 N/m

x = compression = ?

Therefore,

<u>x = 0.0734 m = 7.34 cm</u>

8 0

3 years ago

What is the "basics" of a proper experiment?

lara31 [8.8K]

Answer:

sorry in my sense, an experiment once only changes one variable and need a control setup for experimental setup to make sure is fair test

5 0

3 years ago

The mass of M1 = 12 Daltons and it has a speed of v1 = 200 m/s. The mass of M2 = 4 Daltons. What was the total momentum of the s

svet-max [94.6K]

Answer:

The total momentum is $p__{T }} =(2400 -4 v_2) \ Dalton \cdot m/s$

Explanation:

The diagram illustration this system is shown on the first uploaded image (From physics animation)

From the question we are told that

The mass of the first object is $M_1 = 12 \ Dalton$

The speed of the first mass is $v_1 = 200 \ m/s$

The mass of the second object is $M_2 = 4 \ Dalton$

The speed of the second object is assumed to be $- v_2$

The total momentum of the system is the combined momentum of both object which is mathematically represented as

$p__{T }} = M_1 v_1 + M_2 v_2$

substituting values

$p__{T }} = 12 * 200 + 4 * (-v_2)$

$p__{T }} =(2400 -4 v_2) \ Dalton \cdot m/s$

7 0

3 years ago