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stepladder [879]
3 years ago
7

Can Someone help me ASAP please and thx

Physics
2 answers:
Tanya [424]3 years ago
5 0
It could be rock music because of his face expresion
BartSMP [9]3 years ago
4 0

Answer:

could be rock or maybe hip pop/ pop

Explanation:

You might be interested in
Will give brainlist!! Please help!!
Marrrta [24]

Answer:Electromagnetic Energy Example One

activity: cellphones

type of electromagnetic: radio waves

description: we all use our phones to make phone calls and to send a text!

Electromagnetic Energy Example two

activity: microwave

type of electromagnetic: microwave radiation

description: The microwave radiation is absorbed by water molecules in the food which converts to heat intern heats the food do to high levels of radiation being emitted into the food!  

Explanation:

i hope this helps you sorry if it doesn't

5 0
2 years ago
What is Force &amp; how many types of Force express with example <br><br><br><br>​
ehidna [41]

Answer:

The force is pull or push acting on the body which tends to change its state of rest or of motion is called force.

There are two types of force:

1.Contact force

2. Non-Contact

7 0
3 years ago
Bodies weighing 1 kilogram and 5 kilograms lie on a smooth horizontal surface. If a traction force of 0.6 N acts on another 5 kg
natima [27]

0.6/5,1,5

so calculate it

not so sure though

6 0
3 years ago
Make I the subject<br> E=VIt
slava [35]

To Make I the subject you need to get it by itself. To do this divide both sides by V and t:

I = E/Vt

5 0
3 years ago
The temperature and time t given in hours from 0 to 24 after midnight in downtown mathville is given by t=10-5 sin(pi/12 t) degr
Dvinal [7]

Answer:

T_A_v_g=9.918192559$^{\circ}C

Explanation:

The problem tell us that the temperature as function of time in downtown mathville is given by:

T(t)=10-5*sin(\frac{\pi}{12t})

The average temperature over a given interval can be calculated as:

T_a_v_g=\frac{T_o+T_f}{2}

Where:

T_o=Initial\hspace{3}temperature\\T_f=Final\hspace{3}temperature

So, the initial temperature in this case, would be the temperature at noon, and the final temperature would be the temperature at midnight:

Therefore:

T_o=T(12)=10-5*sin(\frac{\pi}{12*12}) =9.890925575$^{\circ}C

T_f=T(24)=10-5*sin(\frac{\pi}{12*24}) =9.945459543$^{\circ}C

Hence, the average temperature between noon and midnight is:

T_A_v_g=\frac{9.890925575+9.945459543}{2}=9.918192559$^{\circ}C

3 0
2 years ago
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