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Maksim231197 [3]
1 year ago
8

A 500-W heating coil designed to operate from 110V is made of Nichrome wire 0.500 mm in diameter. (b) What If? Now consider the

variation of resistivity with temperature. What power is delivered to the coil of part (a) when it is warmed to 1200°C ?
Physics
1 answer:
melamori03 [73]1 year ago
6 0

The power delivered to the coil is 721.31 Watts

<h3>How to determine the power</h3>

Given that;

  • Power of the heating coil = 500W
  • Voltage = 110V
  • Diameter of the Nichrome wire = 0. 500mm, radius = 0. 500/2 = 0. 00025m

But the formula for power is given a;

Power, P = V²/R

Then , R = V²/P

R = (110)²/ 500 = 24. 2Ω

To determine the length,

Length, L = RA/ ρ

L = 24. 2 × ( 0. 0025)² × 3. 142/ 10^-6

L = 4. 32m

We also have that;

Resistance, R = Ro( 1 + α ΔT)

R = 24. 2 ( 1 + 0. 0004 × 1180)

R = 35. 62Ω

Current, I = V R

Current, I = 110/24.2 = 4. 5 A

Power delivered = I²R =  (4.5)² × 35. 62 = 721.31 Watts

Thus, the power delivered to the coil is 721.31 Watts

Learn more about power here:

brainly.com/question/24858512

#SPJ4

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A 0.950 kg block is attached to a spring with spring constant 16.0 N/m . While the block is sitting at rest, a student hits it w
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Answer:

Explanation:

Given that,

Mass attached m = 0.95kg

Spring constant k = 16N/m

Instantaneous speed v = 36cm/s = 0.36m/s

Amplitude A=?

When x = 0.7A

Using conservation of energy

∆K.E + ∆P.E = 0

K.E(final) — K.E(initial) + P.E(final) — P.E(initial) = 0

At the beginning immediately the hammer hits the mass, the potential energy is 0J, Therefore, P.E(initial) = 0J, so the speed is maximum.

Also, at the end, at maximum displacement, the speed is zero, therefore, K.E(final) = 0

So, the equation becomes

— K.E(initial) + P.E(final) = 0

K.E(initial) = P.E(final)

½mv² = ½kA²

mv² = kA²

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0.12312 = 16•A²

A² = 0.12312/16

A² = 0.007695

A = √0.007695

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B. Speed at x = 0.7A

Using the same principle above

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v = √0.0635

v = 0.252 m/s

v = 25.2 cm/s

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