The power delivered to the coil is 721.31 Watts
<h3>How to determine the power</h3>
Given that;
- Power of the heating coil = 500W
- Voltage = 110V
- Diameter of the Nichrome wire = 0. 500mm, radius = 0. 500/2 = 0. 00025m
But the formula for power is given a;
Power, P = V²/R
Then , R = V²/P
R = (110)²/ 500 = 24. 2Ω
To determine the length,
Length, L = RA/ ρ
L = 24. 2 × ( 0. 0025)² × 3. 142/ 10^-6
L = 4. 32m
We also have that;
Resistance, R = Ro( 1 + α ΔT)
R = 24. 2 ( 1 + 0. 0004 × 1180)
R = 35. 62Ω
Current, I = V R
Current, I = 110/24.2 = 4. 5 A
Power delivered = I²R = (4.5)² × 35. 62 = 721.31 Watts
Thus, the power delivered to the coil is 721.31 Watts
Learn more about power here:
brainly.com/question/24858512
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