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Maksim231197 [3]

2 years ago

8

A 500-W heating coil designed to operate from 110V is made of Nichrome wire 0.500 mm in diameter. (b) What If? Now consider the

variation of resistivity with temperature. What power is delivered to the coil of part (a) when it is warmed to 1200°C ?

1 answer:

melamori03 [73]2 years ago

6 0

The power delivered to the coil is 721.31 Watts

<h3>How to determine the power</h3>

Given that;

Power of the heating coil = 500W
Voltage = 110V
Diameter of the Nichrome wire = 0. 500mm, radius = 0. 500/2 = 0. 00025m

But the formula for power is given a;

Power, P = V²/R

Then , R = V²/P

R = (110)²/ 500 = 24. 2Ω

To determine the length,

Length, L = RA/ ρ

L = 24. 2 × ( 0. 0025)² × 3. 142/ 10^-6

L = 4. 32m

We also have that;

Resistance, R = Ro( 1 + α ΔT)

R = 24. 2 ( 1 + 0. 0004 × 1180)

R = 35. 62Ω

Current, I = V R

Current, I = 110/24.2 = 4. 5 A

Power delivered = I²R = (4.5)² × 35. 62 = 721.31 Watts

Thus, the power delivered to the coil is 721.31 Watts

Learn more about power here:

brainly.com/question/24858512

#SPJ4

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3 years ago

A sphere of radius 0.081029 m is made of aluminum. It is submerged in flowing water with a temperature of 25 °C that results in

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its surface temperature = 54.84 ° C

Explanation:

The density of aluminium $(\rho)$ = 2700 kg/m ³

Heat capacity $( c_p)$ = 897 J/Kg.K

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$T \infty$ = 25 °C

$T_i$ = 124.978 °C

time (t) = 767.276 s

Using the formula :

$\frac{T-T_{ \infty} }{T_i - T_{\infty}}= e^{-\frac{hA}{\rho V c_p}}*t$

where.

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$\frac{T-25 }{124.978 - 25}= e^{{-0.001576}*767.276$

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