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Maksim231197 [3]
1 year ago
8

A 500-W heating coil designed to operate from 110V is made of Nichrome wire 0.500 mm in diameter. (b) What If? Now consider the

variation of resistivity with temperature. What power is delivered to the coil of part (a) when it is warmed to 1200°C ?
Physics
1 answer:
melamori03 [73]1 year ago
6 0

The power delivered to the coil is 721.31 Watts

<h3>How to determine the power</h3>

Given that;

  • Power of the heating coil = 500W
  • Voltage = 110V
  • Diameter of the Nichrome wire = 0. 500mm, radius = 0. 500/2 = 0. 00025m

But the formula for power is given a;

Power, P = V²/R

Then , R = V²/P

R = (110)²/ 500 = 24. 2Ω

To determine the length,

Length, L = RA/ ρ

L = 24. 2 × ( 0. 0025)² × 3. 142/ 10^-6

L = 4. 32m

We also have that;

Resistance, R = Ro( 1 + α ΔT)

R = 24. 2 ( 1 + 0. 0004 × 1180)

R = 35. 62Ω

Current, I = V R

Current, I = 110/24.2 = 4. 5 A

Power delivered = I²R =  (4.5)² × 35. 62 = 721.31 Watts

Thus, the power delivered to the coil is 721.31 Watts

Learn more about power here:

brainly.com/question/24858512

#SPJ4

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Answer:

a) t = H/v0

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Explanation:

Hi there!

a)The position of the balls can be calculated using the following equation:

y = y0 + v0 · t + 1/2 · g · t²

Where:

y = height of the ball at time t.

y0 = initial height.

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g = acceleration due to gravity.

t = time.

For the ball that is thrown upwards, the initial height is zero, then, the equation can be written as follows:

y = v0 · t + 1/2 · g · t²

The second ball is initially at a height H and the initial velocity is zero. The equation of height for the second ball will be:

y = H + 1/2 · g · t²

When the two balls collide, their height is the same. Then, equalizing both equations we can obtain the time at which they collide:

v0 · t + 1/2 · g · t² = H + 1/2 · g · t²

v0 · t = H

t = H/v0

b) When the first ball is at the highest point its velocity is zero. Using the equation of velocity we can find the time at which the ball is at that point. The equation of velocity is the following:

v = v0 + g · t

At the highest point v = 0.

0 = v0 + g · t

Solving for t:

-v0/g = t

The time at which the first ball is at the highest point is t = -v0/g

The time at which both balls collide was calculated above:

t = H/v0

Then, equalizing both times and solving for H:

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h=15.27m

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Since at maximum height the vertical velocity must be null it's better to use the formula:

v_f^2=v_i^2+2ad

We will use this formula for the vertical direction, choosing the upward direction as the positive one, so we have:

0=v_i^2+2ah

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Answer:

\boxed {\boxed {\sf a= -7 \ m/s^2}}

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