All categories

3 years ago

What do you call material formed by weathering that is then eroded and deposited

Chemistry

1 answer:

miskamm [114]3 years ago

5 0

Answer: The material formed by weathering that is then eroded and deposited is called SEDIMENTS.

Explanation:

Weathering is the process by which rocks are broken down to form Sediments. There are three forces that can cause weathering of a rock they include:

- Biological weathering: example tree roots, and lichens.

- Chemical weathering: example, water, acid, or gases.

- Mechanical weathering: example, wind, rain, water freezing.

These Sediments that are generated during the course of weathering is moved from one place to another through a natural force called EROSION. The dropping of the Sediments in a new place is known as deposition. The collective effects of weathering,erosion and deposition leads to:

- landslides

-Changes in shape, size and texture of land forms.

- soil formation

- washes soil, pollutants, harmful sediments into water ways. I hope this helps, thanks.

You might be interested in

In your own words, describe in as much detail as possible, what is air made of.

Advocard [28]

Answer:

nitrogen, oxygen, argon, carbon dioxide, neon, helium, krypton, hydrogen, and xenon. It does not include water vapor because the amount of vapor changes based on humidity and temperature.

3 0

3 years ago

Read 2 more answers

What mass of solid CaSO4 would need to be added in order to make 1.2L of a 0.75M solution?

liberstina [14]

Answer:

120

Explanation:

4 0

2 years ago

Nitrogen dioxide gas is dark brown in color and remains in equilibrium with dinitrogen tetroxide gas, which is colorless.

sukhopar [10]

Answer:

This reaction is exothermic because the system shifted to the left on heating.

Explanation:

2NO₂ (g) ⇌ N₂O₄(g)

Reactant => NO₂ (dark brown in color)

Product => N₂O₄ (colorless)

From the question given above, we were told that when the reaction at equilibrium was moved from room temperature to a higher temperature, the mixture turned dark brown in color.

This simply means that the reaction does not like heat. Hence the reaction is exothermic reaction.

Also, we can see that when the temperature was increased, the reaction turned dark brown in color indicating that the increase in the temperature favors the backward reaction (i.e the equilibrium shift to the left) as NO₂ which is the reactant is dark brown in color. This again indicates that the reaction is exothermic because an increase in the temperature of an exothermic reaction will shift the equilibrium position to the left.

Therefore, we can conclude that:

The reaction is exothermic because the system shifted to the left on heating.

8 0

3 years ago

In which of the following cases will the LEAST time be required to arrive at equilibrium? K below refers to the equilibrium cons

mylen [45]

Answer: Option (4) is the correct answer.

Explanation:

It is known that equilibrium constant is represented as follows for any general reaction.

$A + B \rightarrow C + D$

K = $\frac{[C][D]}{[A][B]}$

As equilibrium constant is directly proportional to the concentration of products so more is the value of equilibrium constant more will be the number of products formed.

As a result, more is the time taken by the reaction to reach towards equilibrium. Whereas smaller is the value of equilibrium constant more rapidly it will reach towards the equilibrium.

Thus, we can conclude that cases where K is a very small number will require the LEAST time to arrive at equilibrium.

8 0

3 years ago

Use the tabulated half-cell potentials to calculate the equilibrium constant (K) for the following balanced redox reaction at 25

o-na [289]

The equation Eºcell = 0.0592/n logK must be used to find n and also Eºcell
2 Al(s) + 3 Mg2+(aq) → 2 Al3+(aq) + 3 Mg(s) Al3+ +3e- --> Al Eº = -1.66 V Mg2+ +2e- -->Mg Eº = -2.37V
To balance the equation, 6 moles of electrons must be transferred (2 Al and 3 Mg). This will be the value of n in the equation.
To find Eºcell, you need the reduction potentials which should be given in a table, and given above. Eºcell = -1.66 - (-2.37) = 0.71 V log K = Eºcell x n/0.0592 = 0.71 x 6/0.0592 log K = 71.95 K = 10^71.95 K = 1.1x10^72

6 0

3 years ago