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Georgia [21]
3 years ago
9

g Select the correct statements. I. Reduction is the loss of electrons, and oxidation is the gain of electrons II. Reduction is

the gain of electrons, and oxidation is the loss of electrons III. The reactant that is reduced is also called the reducing agent, and the reactant that is oxidized is called the oxidizing agent. IV. The reactant that is oxidized is also called the reducing agent, and the reactant that is reduced is called the oxidizing agent. V. The sum of all the oxidation numbers in a compound is equal to the charge of that compound. A. I and III only B. II and IV only C. I, III, and V only D. II, IV, and V only E. V only
Chemistry
1 answer:
Karolina [17]3 years ago
6 0

<u>Answer:</u> The correct answer is Option D.

<u>Explanation:</u>

Reduction reaction is defined as the reaction in which a substance gains electrons. Here, the oxidation state of the substance decreases.

X^{n+}+ne^-\rightarrow X

Oxidizing agents are the agents that helps in the oxidation of other substance and itself gets reduced. These agents undergoes reduction reactions.

Oxidation reaction is defined as the reaction in which a substance looses its electrons. Here, oxidation state of the substance increases.

X\rightarrow X^{n+}+ne^-

Reducing agents are the agents that helps in the reduction of the other substance and itself gets oxidized. These agents undergoes reduction reactions.

Oxidation state is the number which is given to an atom when it looses or gains electron. It is written as a superscript. In a compound, the total charge is equal to the sum of the charges of all atoms in that compound. <u>For Example:</u> In MnO_4^-, manganese has +7 oxidation number and oxygen has -2.

So, the charge on the compound = [=7+(4\times (-2))]=-1

Hence, the correct answer is Option D.

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For a particular isomer of C 8 H 18 , C8H18, the combustion reaction produces 5104.1 kJ 5104.1 kJ of heat per mole of C 8 H 18 (
vlada-n [284]

Answer:

The standard enthalpy of formation of this isomer of octane is -220.1 kJ/mol

Explanation:

Step 1: Data given

The combustion reaction of octane produces 5104.1 kJ per mol octane

Step 2: The balanced equation

C8H18(g) + 12.5 O2 ⟶ 8CO2 (g) + 9 H2O (g)  ∆H°rxn = -5104.1 kJ/mol

Step 3:

∆H°rxn = ∆H°f of products minus the ∆H° of reactants

∆H°rxn = ∆H°f products - [∆H°f reactants]

-5104.1 kJ/mol = (8*∆H°fCO2 + 9*∆H°fH20) - (∆H°fC8H18 + 12.5∆H°fO2)

∆H°f C8H18 = ∆H°f 8CO2 + ∆H°f 9H2O+ 5104.1 kJ/mol

∆H°f C8H18 = 8 * (-393.5 kJ)/mol + 9 * (-241.8 kJ/mol)] + 5104.1 kJ /mol

∆H°f C8H18 = -220.1 kJ/mol

The standard enthalpy of formation of this isomer of octane is -220.1 kJ/mol

7 0
3 years ago
Which elements can have expanded octets?
PSYCHO15rus [73]

Answer:

Sulfur, phosphorus, silicon, and chlorine are common examples of elements that form an expanded octet.

Explanation:

Phosphorus pentachloride (PCl5) and sulfur hexafluoride (SF6) are examples of molecules that deviate from the octet rule by having more than 8 electrons around the central atom

7 0
2 years ago
Why is the beach such a nice place to be on a hot day?
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Bcz you’re able to wear something fresh, get a tan if you’d want, play volleyball or go out to swim in the cold ocean that feels so good when it’s hot !
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3 years ago
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6 0
4 years ago
4.2 L of a gas has a pressure of 560mmHg at 72⁰F. What is the temperature at760mmHg if the volume is still 4.2 L? (5 pts)
IgorLugansk [536]

Answer:

The temperature at 760mmHg if the volume is still 4.2 L is 400.862 K

Explanation:

Gay Lussac's law indicates that when there is a constant volume, as the temperature increases, the pressure of the gas increases. And when the temperature is decreased, the pressure of the gas decreases. This law can be expressed mathematically as follows:

\frac{P}{T} =k

Having an initial state 1 and a final state 2, the following is true:

\frac{P1}{T1} =\frac{P2}{T2}

In this case:

  • P1= 560 mmHg
  • T1= 72 F= 295.372 K (being 32 F= 273.15 K)
  • P2= 760 mmHg
  • T2= ?

Replacing:

\frac{560 mmHg}{295.372 K} =\frac{760 mmHg}{T2}

Solving:

T2= 760 mmHg*\frac{295.372 K}{560 mmHg}

T2= 400.862 K

8 0
3 years ago
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