<h3>
<u>Answer;</u></h3>
= 5.102 m
<h3><u>Explanation;</u></h3>
The total energy, i.e. sum of kinetic and potential energy, is constant.
That is; E = KE + PE
Initially, PE = 0 and KE = 1/2 mv^2
At maximum height, velocity=0, thus, KE = 0 and PE = mgh
Since, total energy is constant (KE converts to PE when the ball is rising).
Therefore, KE = PE
or, 1/2 mv^2 = mgh
or, h = v^2 /2g
= 10^2 / (2x9.8)
=<u> 5.102 m</u>
The displacement of Edward in the westerly direction is determined as 338.32 km.
<h3>What is displacement of Edward?</h3>
The displacement of Edward can be determined from different methods of vector addition. The method applied here is triangular method.
The angle between the 200 km north west and 150 km west = 60 + 90 = 150⁰
The displacement is the side of the triangle facing 150⁰ = R
R² = a² + b² - 2abcosR
R² = 150² + 200² - (2x 150 x 200)xcos(150)
R² = 62,500 - (-51,961.52)
R² = 114,461.52
R = 338.32 km
Learn more about displacement here: brainly.com/question/321442
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Answer:
See explanation
Explanation:
In this exercise, we need to use the law of conservation of angular momentum which is:
I1*W1 + I2*W2 = (I1 + I2)*W2'
Where:
I: moment of innertia.
W: angular velocity
Now let's call 1 the runner and 2, the turntable. the system would be W2'.
The angular speed of the runner, we can calculate that with the following expression:
W = V/r
so:
W1 = 2.5 / 3.6 = 0.694 rad/s
The innertia is calculated with the expression:
I = m*r²
I = 60 * 3.6 = 216 kg.m²
I2 and W2 are provided in the exercise, so, replacing all the data in the conservation of angular momentum, let's solve for W2'
(216*0.694) + (-0.190*81) = (81 + 216)W2'
134.514 = 297W2'
W2' = 134.514 / 297
W2' = 0.453 rad/s
