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mixas84 [53]
3 years ago
12

326L

Chemistry
1 answer:
dalvyx [7]3 years ago
6 0

Answer:

Final number of moles = 0.675 mol

Mass = 2.7 g

Explanation:

Given data:

Initial volume of gas = 2.00 L

Final volume of gas = 2.70 L

Initial number of moles = 0.500 mol

Final number of moles = ?

Solution:

Formula:

V₁/n₁ = V₂/n₂

V₁ = Initial volume

n₁ = Initial number of moles

V₂ = Final volume of gas

n₂ = Final number of moles

Now we will put the values in formula.

2.00 L /0.500 mol = 2.70 L / n₂

n₂ = 2.70 L× 0.500 mol /2.00 L

n₂ = 1.35 L.mol / 2.00 L

n₂ = 0.675 mol

B)

Grams of helium added = ?

Solution:

Mass = number of moles × molar mass

Mass = 0.675 mol× 4 g/mol

Mass = 2.7 g

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Answer:

Iron (Fe)

Explanation:

The number of electrons (-) is usually the same as the number of protons (+) in the atom of the element (unless it is an ion).

The element described has 26 electrons, so we can assume that it has 26 protons as well. The number of protons in an atom is the atomic number of element that the atom is.

Element 26 on the PTE is Iron (Fe), which does rust (oxidation) in air and water.

8 0
3 years ago
A flask contains 0.340 mol of liquid bromine, br2. determine the number of bromine molecules present in the flask.
marshall27 [118]
<span>Avogadro's number represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole. This number can be used to convert the number of atoms or molecules into number of moles. We calculate as follows:

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7 0
3 years ago
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The reaction 2NO(g)+O2(g)−→−2NO2(g) is second order in NO and first order in O2. When [NO]=0.040M, and [O2]=0.035M, the observed
Oksanka [162]

Answer:

(a) The rate of disappearance of O_{2} is: 4.65*10^{-5} M/s

(b) The value of rate constant is: 0.83036 M^{-2}s^{-1}

(c) The units of rate constant is:  M^{-2}s^{-1}

(d) The rate will increase by a factor of 3.24

Explanation:

The rate of a reaction can be expressed in terms of the concentrations of the reactants and products in accordance with the balanced equation.

For the given reaction:

2NO(g)+O_{2}->2NO_{2}

rate = -\frac{1}{2} \frac{d}{dt}[NO] = -\frac{d}{dt}[O_{2}] = \frac{1}{2}\frac{d}{dt}[NO_{2}] -----(1)

According to the question, the reaction is second order in NO and first order in  O_{2}.

Then we can say that, rate = k[NO]^{2}[O_{2}] -----(2)

where k is the rate constant.

The rate of disappearance of NO is given:

-\frac{d}{dt}[NO] = 9.3*10^{-5} M/s.

(a) From (1), we can get the rate of disappearance of O_{2}.

    Rate of disappearance of  O_{2} = -\frac{d}{dt}[O_{2}] = (0.5)*(9.3*10^{-5}) M/s = 4.65*10^{-5} M/s.

(b) The rate of the reaction can be obtained from (1).

    rate = -\frac{1}{2} \frac{d}{dt}[NO] = (0.5)*(9.3*10^{-5})

    rate = 4.65*10^{-5} M/s

   The value of rate constant can be obtained by using (2).

    rate constant = k = \frac{rate}{[NO]^{2}[O_{2}]}

    k = \frac{4.65*10^{-5}}{(0.040)^{2}(0.035)} = 0.83036 M^{-2}s^{-1}

(c) The units of the rate constant can be obtained from (2).

    k = \frac{rate}{[NO]^{2}[O_{2}]}

    Substituting the units of rate as M/s and concentrations as M, we get:

\frac{Ms^{-1} }{M^{3}} = M^{-2}s^{-1}

(d) The reaction is second order in NO. Rate is proportional to square of the concentration of NO.

     rate\alpha [NO]^{2}

If the concentration of NO increases by a factor of 1.8, the rate will increase by a factor of (1.8)^{2} = 3.24

     

5 0
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34kurt

Physical Change

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6 0
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Answer:

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Explanation:

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