Answer: i thought i knew but nver mind but on the last won it is c i belive
Explanation:
The answer to the question is C
High pressures are necessary to create such reaction so that the particles will be able to overcome electrostatic repulsion. The particles that make up a particular atom are covered by shells of energy that react to different impulses like pressure. When particles are exposed to extreme environmental pressure it has the tendency to split its particles and undergo nuclear fusion successfully.
Answer:

Explanation:
Henry's law states that the solubility of a gas is directly proportional to its partial pressure. The equation may be written as:

Where
is Henry's law constant.
Our strategy will be to identify the Henry's law constant for oxygen given the initial conditions and then use it to find the solubility at different conditions.
Given initially:

Also, at sea level, we have an atmospheric pressure of:

Given mole fraction:

According to Dalton's law of partial pressures, the partial pressure of oxygen is equal to the product of its mole fraction and the total pressure:

Then the equation becomes:

Solve for
:

Now we're given that at an altitude of 12,000 ft, the atmospheric pressure is now:

Apply Henry's law using the constant we found:
