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emmainna [20.7K]
3 years ago
5

What are cells? Check all that apply.

Chemistry
1 answer:
beks73 [17]3 years ago
6 0

Answer:

the basic structural and functional unit of all living beings

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How many grams are in 1.76 x 10^23 atoms of iodine
Mariana [72]

Answer:

\boxed {\boxed {\sf About \ 37.1 \ grams \ of \ iodine }}

Explanation:

To convert from atoms to grams, you must first convert atoms to moles, then moles to grams.

1. Convert Atoms to Moles

To convert atoms to grams, Avogadro's number must be used.

6.022*10^{23}

This number tells us the number of particles (atoms, molecules, ions, etc.) in 1 mole. In this case, the particles are atoms of iodine.

\frac{6.022*10^{23} \ atoms \ I  }{1 \ mol \ I}

Multiply the given number of atoms by Avogadro's number.

1.76*10^{23} \ atoms \ I*\frac{6.022*10^{23} \ atoms \ I  }{1 \ mol \ I}

Flip the fraction so the atoms of iodine will cancel out.

1.76*10^{23} \ atoms \ I*\frac{  1 \ mol \ I}{6.022*10^{23} \ atoms \ I}

1.76*10^{23}* \frac{1 \ mol \ I}{6.022*10^{23} }

Multiply so the problem condenses into 1 fraction.

\frac{1.76*10^{23} \ mol \ I}{6.022*10^{23} }

0.2922617071 \ mol \ I

2. Convert Moles to Grams

Now we must use the molar mass of iodine, which is found on the Periodic Table.

  • Iodine Molar Mass: 126.9045 g/mol

Use this mass as a fraction.

\frac{ 126.9045 \ g\ I }{ 1 \ mol \ I}

Multiply this fraction by the number of moles found above.

0.2922617071 \ mol \ I*\frac{ 126.9045 \ g\ I }{ 1 \ mol \ I}

Multiply. The moles of iodine will cancel.

0.2922617071 *\frac{ 126.9045 \ g\ I }{ 1 }

The 1 as a denominator is insignificant.

0.2922617071 *{ 126.9045 \ g\ I }

37.08932581 \ g \ I

3. Round

The original measurement of 1.76*10^23 has 3 significant figures (1, 7, and 6). Therefore we must round our answer to 3 sig figs. For this answer, that is the tenths place.

37.08932581 \ g \ I

The 8 in the hundredth place tells us to round the 0 up to a 1.

\approx 37.1\ g \ I

There is about <u>37.1 grams of iodine </u>in 1.76*10^23 atoms.

5 0
3 years ago
What is the name for C2I3
Sidana [21]

Answer: The correct name for the compound C_2I_3  is, Dicarbon triiodide.

Explanation:

C_2I_3 is a covalent compound because in this compound the sharing of electrons takes place between carbon and iodine.. Both the elements are non-metals. Hence, it will form covalent bond.

The naming of covalent compound is given by:

The less electronegative element is written first.

The more electronegative element is written second. Then a suffix is added with it. The suffix added is '-ide'.

If atoms of an element is greater than 1, then prefixes are added which are 'mono' for 1 atom, 'di' for 2 atoms, 'tri' for 3 atoms and so on.

Hence, the correct name for the compound C_2I_3  is, Dicarbon triiodide..

4 0
2 years ago
Given this reaction, N2O4(g) 2NO2(g), what shifts will occur if Q = K?
MAXImum [283]

Answer:

It shifts to the left

Explanation:

7 0
3 years ago
this element has an atomic number lower than that of aluminum and one less valence electrons then the Group 16 elements
ahrayia [7]
This element is nitrogen (N)
6 0
2 years ago
If the forward reaction goes close to completion and has a high yield, what is the expected value of the equilibrium constant (k
Anna007 [38]
If the forward reaction goes close to completion and has a high yield, that means the concentration of products will be higher than the concentration of reactants. 

<span>So if the concentration of products is higher, Kc (equilibrium constant) will be greater than 1.
</span><span>
Recall the calculation for the equilibrium constant for reaction. Picture below might help you.</span>

8 0
3 years ago
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