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alexdok [17]
2 years ago
6

Determine the formula weight of Ca(no3)2

Chemistry
1 answer:
Zanzabum2 years ago
3 0

Answer:

the formula is 164.088 g/mol

Explanation:

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Korolek [52]

Answer:

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Explanation:

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6 0
2 years ago
Electrons returning to the ground state from varying excited states always:
nata0808 [166]

Answer:

produce characteristic sets of energies, depending on the differences in energy between the excited states and ground state

Explanation:

The electron is jumped into higher level and back into lower level by absorbing and releasing the energy.

The process is called excitation and de-excitation.

Excitation:

When the energy is provided to the atom the electrons by absorbing the energy jump to the higher energy levels. This process is called excitation. The amount of energy absorbed by the electron is exactly equal to the energy difference of orbits.  For example if electron jumped from K to L it must absorbed the energy which is equal the energy difference of these two level. The excited electron thus move back to lower energy level which is K by releasing the energy because electron can not stay longer in higher energy level and comes to ground state.

De-excitation:

When the excited electron fall back to the lower energy levels the energy is released in the form of radiations. this energy is exactly equal to the energy difference between the orbits. The characteristics bright colors are due to the these emitted radiations. These emitted radiations can be seen if they are fall in the visible region of spectrum

6 0
3 years ago
What is the full form of alcl3​
Likurg_2 [28]

Answer:

Aluminum Chloride

Explanation:

8 0
3 years ago
Is the equation Ag2O ----> Ag+ O2 balanced
maw [93]
Ok so simple 1Ag2O ---> 1Ag+1O2 do u understand how I got that????
4 0
3 years ago
Read 2 more answers
Na2S2O3 + AgBr NaBr + Na3ſAg(S203)2] What is
gtnhenbr [62]

Answer:

Mass of NaBr produced  = 23.67 g

Explanation:

Given data:

Mass of AgBr = 42.7 g

Mass of NaBr produced = ?

Solution:

Chemical equation:

2Na₂S₂O₃ + AgBr    →    NaBr + Na₃(Ag(S₂O₃)₂

Number of moles of AgBr:

Number of moles = mass/molar mass

Number of moles = 42.7 g/ 187.7 g/mol

Number of moles = 0.23 mol

now we will compare the moles of AgBr with NaBr.

             AgBr        :         NaBr

                1            :           1

              0.23       :         0.23

Mass of NaBr:

Mass = number of moles × molar mass

Mass = 0.23 mol × 102.89 g/mol

Mass = 23.67 g

8 0
2 years ago
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