Can some help me out on some science ?

A train traveled from Station A to Station B at an average speed of 80 kilometers per hour and then from Station B to Station C

Vinil7 [7]

Answer:

1)

75 kmh⁻¹

2)

75 kmh⁻¹

Explanation:

1)

$v_{ab}$ = Speed of train from station A to station B = 80 kmh⁻¹

$d_{ab}$ = distance traveled from station A to station B

$t_{ab}$ = time of travel between station A to station B

we know that

$Time = \frac{distance}{speed}$

$t_{ab} = \frac{d_{ab}}{v_{ab}} = \frac{d_{ab}}{80}$

$d_{bc}$ = distance traveled from station B to station C

$v_{bc}$ = Speed of train from station B to station C = 60 kmh⁻¹

$t_{bc} = \frac{d_{bc}}{v_{bc}} = \frac{d_{bc}}{60}$

Total distance traveled is given as

$d = d_{ab} + d_{bc}$

Total time of travel is given as

$t = t_{ab} + t_{bc}$

Average speed is given as

$v_{avg} = \frac{d}{t} \\v_{avg} = \frac{d_{ab} + d_{bc}}{t_{ab} + t_{bc}}\\v_{avg} = \frac{d_{ab} + d_{bc}}{(\frac{d_{ab}}{80} ) + (\frac{d_{bc}}{60} ) }$

Given that :

$d_{ab} = 4 d_{bc}$

So

$v_{avg} = \frac{4 d_{bc} + d_{bc}}{(\frac{4 d_{bc}}{80} ) + (\frac{d_{bc}}{60} ) }\\v_{avg} = \frac{4 + 1}{(\frac{4 }{80} ) + (\frac{1}{60} ) }\\v_{avg} = 75 kmh^{-1}$

2)

$v_{ab}$ = Speed of train from station A to station B = 80 kmh⁻¹

$t_{ab}$ = time of travel between station A to station B

$d_{ab}$ = distance traveled from station A to station B

we know that

$distance = (speed) (time)$

$d_{ab} = v_{ab} t_{ab}\\d_{ab} = 80 t_{ab}$

$d_{bc}$ = distance traveled from station B to station C

$v_{bc}$ = Speed of train from station B to station C = 60 kmh⁻¹

$t_{bc}$ = time of travel for train from station B to station C

we know that

$distance = (speed) (time)$

$d_{bc} = v_{bc} t_{bc}\\d_{bc} = 60 t_{bc}$

Total distance traveled is given as

$d = d_{ab} + d_{bc}\\d = 80 t_{ab} + 60 t_{bc}$

Total time of travel is given as

$t = t_{ab} + t_{bc}$

Average speed is given as

$v_{avg} = \frac{d}{t} \\v_{avg} = \frac{d_{ab} + d_{bc}}{t_{ab} + t_{bc}}\\v_{avg} = \frac{80 t_{ab} + 60 t_{bc}}{t_{ab} + t_{bc}}$

Given that :

$t_{ab} = 3 t_{bc}$

So

$v_{avg} = \frac{80 t_{ab} + 60 t_{bc}}{t_{ab} + t_{bc}}\\v_{avg} = \frac{80 (3) t_{bc} + 60 t_{bc}}{(3) t_{bc} + t_{bc}}\\v_{avg} = \frac{(300) t_{bc}}{(4) t_{bc}}\\v_{avg} = 75 kmh^{-1}$

4 0

2 years ago

Match the lithification processes.

Varvara68 [4.7K]

Answer:

ReCrystallization

Contact pressure causing grains to "grow" together.

It's a metamorphic process used to rearrange the atoms of the minerals in order to modify them in to the required form under the specific temperature and pressure. For example conversion of limestone into marble.

Cementation:

Precipitation of bonding agents between grains.

Cementation is the process in which the minerals in the form of fluid fills in spaces between the grains and binds them together upon crystallizing.

Compaction:

Increase in density due to weight of overburden.

Compaction as it's name indicate is the compaction of the sediments due to the heavy weight of the rocks which reduce their size and increase their density.

5 0

2 years ago

When an ocean plate converges with another plate, what is created on the seafloor at the line of convergence?

drek231 [11]

When two oceanic plates meet, the process of subduction occurs. During this, the denser plate slips underneath the lighter one, creating a subduction zone. In these subduction zones, a trench is formed.
Trenches are deep crevices on the ocean floor and are home to many different marine species.

5 0

2 years ago

While the change in blank will remain the same during a collision, the force needed to bring an object to a stop can be blank if

Ahat [919]

Explanation :

There are two types of collision i.e. elastic and elastic collision.

Elastic collision : In this type of collision, the total momentum and the kinetic energy of the particles remains constant.
Inelastic collision : In this type of collision, only the momentum remains constant while there is some loss of kinetic energy occurs.

From Newton's second law,

F = m a

a is the rate of change of velocity.

$F=m\dfrac{v}{t}$

There is a inverse relation between the force and the time of collision.

The change in momentum will remain the same during a collision, the force needed to bring an object to a stop can be increased if the time of the collision is decreased.

6 0

2 years ago

Read 2 more answers

Movement of a stationary object (2words)

Whitepunk [10]

Induced motion or movement

6 0

2 years ago