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ser-zykov [4K]
3 years ago
10

Which formula can be used to find the tangential speed of an orbiting object? v = StartFraction 2 pi r over T EndFraction v = St

artFraction square root of 2 pi r over T EndFraction v = GStartFraction m Subscript central Baseline over r EndFraction v = rStartFraction (m Subscript central Baseline) over G EndFraction
Physics
2 answers:
lys-0071 [83]3 years ago
8 0

Answer:

It's A v=2pi/T

Explanation:

I took the test and got it correct.

Anvisha [2.4K]3 years ago
6 0

Answer:

a

Explanation:

right on quiz edge 2020

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Suppose that a comet that was seen in 563 A.D. by Chinese astronomers was spotted again in year 1951. Assume the time between ob
Mars2501 [29]

Answer:

a=2.77*10^{13}m

R_a=5.49*10^{13}m

Explanation:

The period of the comet is the time it takes to do a complete orbit:

T=1951-(-563)=2514 years

writen in seconds:

2514years*\frac{3,154*10^7s}{1year}=7.93 *10^{10}s

Since the eccentricity is greater than 0 but lower than 1 you can know that the trajectory is an ellipse.

Therefore, if the mass of the sun is aprox. 1.99e30 kg, and you assume it to be much larger than the mass of the comet, you can use Kepler's law of periods to calculate the semimajor axis:

T^2=\frac{4\pi^2}{Gm_{sun}}a^3\\ a=\sqrt[3]{\frac{Gm_{sun}T^2}{4\pi^2} } \\a=1.50*10^{6}m

Then, using the law of orbits, you can calculate the greatest distance from the sun, which is called aphelion:

R_a=a(1+e)\\R_a=2.77*10^{13}(1.986)\\R_a=5.49*10^{13}m

8 0
3 years ago
When a 40V battery is connected across an unknown resistor there is a current of 100 ma  in the circuit.
amm1812

Answer:

R = 400 ohms.

Explanation: Voltage of the battery, V = 40 V. Current in the unknown resistor I = 100mA. Let R is the resistance of the resistor. It can be calculated using Ohm's law it gives the relationship between the voltage, resistance and current.. R = V/I. R = 40 V/10-¹A. R = 400 Ohm's. So, the value of the resistance of the resistor is 400 Ohm's

4 0
2 years ago
Read 2 more answers
Relativistic kinetic energy is conserved in all reference frames. True O False
Free_Kalibri [48]

Answer:

i think it is true

Explanation:

7 0
2 years ago
A push on a 1-kilogram brick accelerates the brick. Neglecting friction, to equally accelerate a 10-kilogram brick, one would ha
olga55 [171]
I believe the answer is C. With just as much force.

Hope this helps
4 0
3 years ago
A cylinder has 500 cm3 of water. After a mass of 100 grams of sand is poured into the cylinder and all air bubbles are removed b
Nina [5.8K]

Answer: SG = 2.67

Specific gravity of the sand is 2.67

Explanation:

Specific gravity = density of material/density of water

Given;

Mass of sand m = 100g

Volume of sand = volume of water displaced

Vs = 537.5cm^3 - 500 cm^3

Vs = 37.5cm^3

Density of sand = m/Vs = 100g/37.5 cm^3

Ds = 2.67g/cm^3

Density of water Dw = 1.00 g/cm^3

Therefore, the specific gravity of sand is

SG = Ds/Dw

SG = (2.67g/cm^3)/(1.00g/cm^3)

SG = 2.67

Specific gravity of the sand is 2.67

3 0
3 years ago
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