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ser-zykov [4K]
3 years ago
10

Which formula can be used to find the tangential speed of an orbiting object? v = StartFraction 2 pi r over T EndFraction v = St

artFraction square root of 2 pi r over T EndFraction v = GStartFraction m Subscript central Baseline over r EndFraction v = rStartFraction (m Subscript central Baseline) over G EndFraction
Physics
2 answers:
lys-0071 [83]3 years ago
8 0

Answer:

It's A v=2pi/T

Explanation:

I took the test and got it correct.

Anvisha [2.4K]3 years ago
6 0

Answer:

a

Explanation:

right on quiz edge 2020

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How does the eye and brain work together to give you perception of color
Nimfa-mama [501]

Answer:

The human eye and brain together translate light into color. Light receptors within the eye transmit messages to the brain, which produces the familiar sensations of color. ... Rather, the surface of an object reflects some colors and absorbs all the others. We perceive only the reflected colors.

Explanation:

8 0
3 years ago
the fireman wishes to direct the flow of water from his hose to the fire at b. determine two possible angles u1 and u2 at which
Lelechka [254]

The two possible angles obtained by using the qudratic equation are;

θ_{1} = 15.10° and θ2 = 73.51°

Given, speed of water = v_{A} = 50ft/s

For the motion along x direction, time period can be calculated as follows:

s_{x} = (v_{A}) _x_{} } t

35 = (50 × cosθ) t

t = 0.64 / cosθ

For the motion in y direction, an equation can be obtained as follows:

s_{y} = (v_{A})_{y}  t +\frac{1}{2} (a_{y} )t^{2}

s_{y} = (-v_{A}sinθ) }  t +\frac{1}{2} (a_{y} )t^{2}

Plugging in the values we get:

-20 = (-50_sinθ) }  t +\frac{1}{2} (-32.2} )t^{2}

-20 = -32tanθ - 10.304sec^{2}θ

Upon solving the above quadratic equation, we get,

tanθ = 0.27 , -3.38

Therefore,

tanθ_{1} = 0.27

θ_{1} = 15.10°

and, tanθ_{2} = -3.38

θ_{2} = 73.51

Learn more about quadratic equation here:

brainly.com/question/17177510

#SPJ4

8 0
7 months ago
A child sleds down a hill with an acceleration of 2.94 m/s2. If her initial speed is 0.0 m/s and her final speed is 17.5 m/s, ho
hram777 [196]

Answer:

The child will take 5.952 seconds to travel from the top of the hill to the bottom.

Explanation:

Given that the child accelerates uniformly and that both initial (v_{o}) and final speeds (v_{f}), measured in meters per second, and acceleration (a), measured in meters per square second, are known, we proceed to use the following kinematic equation to determine the time taken to travel from the top of the hill to the bottom (t), measured in seconds, is:

t = \frac{v_{f}-v_{o}}{a} (1)

If we know that v_{o} = 0\,\frac{m}{s}, v_{f} = 17.5\,\frac{m}{s} and a = 2.94\,\frac{m}{s^{2}}, then the time taken is:

t = \frac{17.5\,\frac{m}{s}-0\,\frac{m}{s} }{2.94\,\frac{m}{s^{2}} }

t = 5.952\,s

The child will take 5.952 seconds to travel from the top of the hill to the bottom.

8 0
3 years ago
True or false an experiment in investigating the effects and development variable on the independent variable
Sergeu [11.5K]

true if you are refering to the desing of the experimnt as it does identify the variable

8 0
2 years ago
How is the scientific use of the term digital different from the common use
Bess [88]
We commonly know refer to something 'digital' has to something electronic that can be visibly seen such as a watch, clock, camera, screen, etc.  It really refers to stored energy or electricity that's not natural.  But the word 'digital' in science refers to the depiction of data<span> or </span>information<span> in </span>figures<span> (such as in a </span>table<span>) in contrast to as a </span>chart<span>, </span>graph<span>, </span>drawing<span>, or other pictorial </span>form.<span>

</span>
7 0
3 years ago
Read 2 more answers
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