Which formula can be used to find the tangential speed of an orbiting object? v = StartFraction 2 pi r over T EndFraction v = St
2 answers:
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Answer:
a) 3673469.39 seconds
b) 6.61×10¹⁴ m
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity = 0.12×3×10⁸ m/s
s = Displacement
a = Acceleration due to gravity = 9.8 m/s²
Equation of motion
Time taken to reach 12% of light speed is 3673469.39 seconds
The distance it would have to travel is 6.61×10¹⁴ m