Answer:
533.33 nm
Explanation:
Since dsinθ = mλ for each slit, where m = order of slit and λ = wavelength of light. Let m' = 10 th order fringe of the first slit of wavelength of light, λ = 640 nm and m"= 12 th order fringe of the second slight of wavelength of light, λ'.
Since the fringes coincide,
m'λ = m"λ'
λ' = m'λ/m"
= 10 × 640 nm/12
= 6400 nm/12
= 533.33 nm
Answer: Magnitude of the average force exerted on the glove by the other boxer is 827.86 N (approximately 828 N).
Explanation: Impulse is defined as the force acting on an object for a short period or interval of time.
Mathematically it is given by the relation:
Impulse = Force
Time
According to the numerical values given in the question, I = 202 Ns and T = 0.244 s
So, Force F =
=
= 827.86 N
Magnitude of the average force exerted on the glove by the other boxer is 827.86 N (approximately 828 N).
Answer:
15.625 watts
Explanation:
Recall that power is defined as the worked performed per unit of time:
Power = Work / time
The work done is Force * distance, so in our case the work is:
Work = 25 M * 5 m = 125 J
Then the power will be:
Power = 125 J / 8 sec = 15.625 watts
Answer:
The time of flight of the ball is 1.06 seconds.
Explanation:
Given 

Also, 

Let us say the velocity in the x-direction is
and in the y-direction is
. And acceleration in the x-direction is
and in the y-direction is
.
Also,
is distance covered in x and y direction respectively. And
is the time taken by the ball to hit the backboard.
We can write
. Where
is velocity of ball.
Now,


Also,
.
Plugging this value in


So, the time of flight of the ball is 1.06 seconds.
Frequency = (speed) / (wavelength)
Frequency = (331 m/s) / (0.6 m) = 551.7 Hz