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siniylev [52]
2 years ago
7

What is a lunar month

Physics
2 answers:
Ira Lisetskai [31]2 years ago
7 0

Answer:

It's the duration between successive new moons. Also called a lunation or synodic month, it has a mean period of 29.53059 days (29 days 12 hours and 44 minutes).

Travka [436]2 years ago
4 0
The adjective lunar is used to describe something that is related to the Moon.
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. Maria walked 1.5 miles south to her house in 0.5 hours. What is her speed in miles per hour?
Simora [160]

1) 3 miles/Hour

The speed is defined as the distance covered divided by the time taken:

v=\frac{d}{t}

where

d = 1.5 mi is the distance

t = 0.5 h is the time taken

Substituting,

v=\frac{1.5}{0.5}=3 mi/h

2) 1.34 m/s south

Velocity, instead, is a vector, so it has both a magnitude and a direction. We have:

d=1.5 mi \cdot 1609 m/mi = 2414 m is the displacement in meters

t=0.5 h \cdot 3600 s/h =1800 s is the time taken in seconds

Substituting,

v=\frac{2414 m}{1800 s}=1.34 m/s

And the direction of the velocity is the same as the displacement, so it is south.

6 0
3 years ago
Helllppp mee!
Fed [463]

Given:

m = 0.14 kg

v = 18 m/s

To find:

Kinetic energy= ?

Explanation:

Kinetic energy of the object is possessed when the object is in motion. It is define as the work done required to accelerate a body from rest to motion. Unit of energy is Joule and it is same as unit of work done. Energy is nothing but the capacity to do work.

Solution:

Kinetic energy of the ball is given by,

Kinetic energy = \frac{1}{2}m v^{2}

m = 0.14 kg

v = 18 m/s

Kinetic energy = \frac{1}{2}(0.14) (18)^{2}

Kinetic energy = 226.8 Joule

5 0
3 years ago
Read 2 more answers
Countries such as Ireland, Germany and the UK use wind turbines to generate power. How does a wind turbine transform energy?
kiruha [24]

Answer:

Rf5 is 6 and I have an article on common strategies for coping

Explanation:

Abdullah and this is my 55 566 and I have an article on common strategies for coping with the value of polynomial 5x and the video will will certainly not cause any harm to you and the thank god that you can please make a gaming video or 6 with gggtgr and the video will will certainly be the same as the one you sent me last night and I will send you a link to the chief 6 on the

3 0
3 years ago
A 16000 kg railroad car travels along on a level frictionless track with a constant speed of 23.0 m/s. A 5400 kg additional load
Alisiya [41]

Answer:

The speed of the car when load is dropped in it is 17.19 m/s.

Explanation:

It is given that,

Mass of the railroad car, m₁ = 16000 kg

Speed of the railroad car, v₁ = 23 m/s

Mass of additional load, m₂ = 5400 kg

The additional load is dropped onto the car. Let v will be its speed. On applying the conservation of momentum as :

m_1v_1=(m_1+m_2)v

v=\dfrac{m_1v_1}{m_1+m_2}

v=\dfrac{16000\ kg\times 23\ m/s}{(16000+5400)\ kg}

v = 17.19 m/s

So, the speed of the car when load is dropped in it is 17.19 m/s. Hence, this is the required solution.

6 0
3 years ago
When discussing what makes a material a good conductor you say, "They must
RSB [31]
Readily accept electron flow            b. right answer 


7 0
3 years ago
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