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alisha [4.7K]
3 years ago
11

A 300 g ball swings in a vertical circle at the end of a 1.3-m-long string. When the ball is at the bottom of the circle, the te

nsion in the string is 13 N.
What is the speed of the ball at that point?
Physics
1 answer:
scoray [572]3 years ago
6 0

Answer:

0.23N for the speed

at the bottom of the circle

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What are the features of nanotechnology? ​
grigory [225]

Answer:

Characteristics of Nanotechnology

Explanation:

Nanotechnology deals with putting things together atom by atom and with structures so small they are invisible to the naked eye. It provides the ability to create materials, devices and systems with fundamentally new functions and properties

7 0
3 years ago
How long it take a train to cover 630km having a speed of 30 km/hr​
noname [10]

Answer:

21 hours

Explanation:

well 30 x 20 = 600 than 21 = 630

4 0
3 years ago
How long does it take light from a camera to travel to the face of someone standing 7 meters away?
mestny [16]

The time taken for the light to travel from the camera to someone standing 7 m away is 2.33×10¯⁸ s

Speed is simply defined as the distance travelled per unit time. Mathematically, it is expressed as:

<h3>Speed = distance / time </h3>

With the above formula, we can obtain the time taken for the light to travel from the camera to someone standing 7 m away. This can be obtained as follow:

Distance = 7 m

Speed of light = 3×10⁸ m/s

<h3>Time =?</h3>

Time = Distance / speed

Time = 7 / 3×10⁸

<h3>Time = 2.33×10¯⁸ s</h3>

Therefore, the time taken for the light to travel from the camera to someone standing 7 m away is 2.33×10¯⁸ s

Learn more: brainly.com/question/14988345

8 0
2 years ago
A shopper weighs 4.00 kg of apples on a supermarket scale whose spring obeys Hooke's law and notes that the spring stretches a d
Irina-Kira [14]

Answer:

a) 0.040625 m

b) 5.02272 J

Explanation:

k = Spring constant

x = Stretched length

F = Force

a)

F=kx\\\Rightarrow k=\frac{F}{x}\\\Rightarrow k=\frac{4\times 9.81}{0.025}\\\Rightarrow k=1569.6\ N/m

F=kx\\\Rightarrow x=\frac{F}{k}\\\Rightarrow x=\frac{6.5\times 9.81}{1569.6}\\\Rightarrow x=0.040625\ m

Extension of the spring would be 0.040625 m

b) Work done in a spring

W=\frac{1}{2}kx^2\\\Rightarrow W=\frac{1}{2}\times 1569.6\times 0.08^2\\\Rightarrow W=5.02272\ J

The work done by the shopper to stretch this spring a total distance of 8.00 cm is 5.02272 J

4 0
3 years ago
Ok ok ik ik this is not the answer but I think you need to hear this
leonid [27]

Answer

oh thanksssss i hope u have a great day

Explanation:

ur a really awesome person and i thank u for that

4 0
2 years ago
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