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Scilla [17]
3 years ago
13

If my candle has a brightness of 15 candela from a distance of 2 meter. What would the brightness be at a distance of 6 meters?

Physics
1 answer:
nata0808 [166]3 years ago
6 0

Answer:

5 candela

Explanation:

Let the candle brightness be B

Let the distance be d

The candle brightness is inversely proportional to the distance

B α 1/d

B = k/d

If my candle has a brightness of 15 candela from a distance of 2 meter, then;

15 = k/2

k = 30

To get the brightness when the distance is 6m;

B = k/d

B = 30/6

B = 5 candela

Hence the brightness will be 5 candela

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2. A pair of narrow, parallel slits sep by 0.25 mm is illuminated by 546 nm green light. The interference pattern is observed on
Agata [3.3K]

Answer:

for the first interference m = 1   y = 2,839 10-3 m

for the second interference m = 2   y = 5,678 10-3 m

Explanation:

The double slit interference phenomenon, for constructive interference is described by the expression

                d sin θ = m λ

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In these experiments in general the observation screen is L >> d, let's use trigonometry to find the angles

           tan θ = y / L

with the angle it is small,

          tan θ = sin θ / cos θ = sin θ

   

we substitute

         sin θ = y / L

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the distance between the central maximum and an interference line is

        y = m λ L / d

let's reduce the magnitudes to the SI system

     λ = 546 nm = 546 10⁻⁹ m

     d = 0.25 mm = 0.25 10⁻³ m

let's substitute the values

      y = m 546 10⁻⁹ 1.3 / 0.25 10⁻³

      y =  m 2,839 10⁻³

the explicit value for a line depends on the value of the integer m, for example

for the first interference m = 1

the distance from the central maximum to the first line is y = 2,839 10-3 m

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the distance from the central maximum to the second line is y = 5,678 10-3 m

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3 years ago
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4vir4ik [10]

Answer:

The answer is explained below.

Explanation:

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