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When boat is sunk into the liquid the net buoyancy on the boat is counterbalanced by weight of the boat
So here weight of the boat = Buoyancy force
let say boat is sunk by distance "h"
now we can say


now by above force balance equation we can write




so boat will sunk by total 5 mm distance
Answer:A
Explanation:Find attached picture file for details
Answer:
both mass take equal time to reach at bottom
Explanation:
As both masses M 1 and M 2 are situated at same height so that the potential energy at top is transformed to kinetic energy at the bottom by applying principle of energy conservation.
PE = KE
Mgh = (1/2)(M)(V^2)
V^2 = 2gh
V = (2gh)^(1/2)
So velocity is independent of mass
For M1
(M_1)(g)(h) = (1/2)(M1)(V^2)
V^2 = 2gh
V = (2gh)^(1/2)
For M2
(M_2)(g)(h) = (1/2)(M2)(V^2)
V^2 = 2gh
V = (2gh)^(1/2)
therefoer speed at bottom too are independent of mass
So we can say both speed are independent of therir respective mass
hence both take equal time to reach at bottom