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zhuklara [117]
2 years ago
9

What is the sun's thickest layer?besides radiation zone?

Physics
2 answers:
makvit [3.9K]2 years ago
3 0
Corona gas star is literally z thickest layer. hope it helped.
enyata [817]2 years ago
3 0
Besides radiation zone, the sun's thickest layer is the corona gas star.
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B) A satellite with mass m orbits the Earth at a radius r. A second satellite also with mass m orbits the
Snezhnost [94]

Answer:

So, given the eqn Fg=G(m1+m2/r^2) where G is the gravitational constant, m is the mass of the satellite and m2 is the mass of the earth and r is the distance from earth to the satellite, the force of earths gravity should be quartered.

Cause (2r)^2 gets turned into (4r^2) where 4r^2 is compared to r^2

Explanation:

6 0
2 years ago
How long does it take a car traveling at 45km/h to travel 100.0 m?
djyliett [7]

Answer:

8 seconds

Explanation:

Since the carspeed is in km/h, we need equal units, so we will make 100.0m 0.1000km.

Then we need to find how long it takes the car to travel 0.1km

We can use the formula distance=speed * time and get

0.1=45 * time

Therefore we get .002222... hours

Multiplying this by 3600 (to get seconds, 60x60), we get 8 seconds

6 0
2 years ago
Read 2 more answers
A boy and his dog run at 3m/s for 4min. How far do they run?
Angelina_Jolie [31]
1) 4min = 4*60 sec = 240 sec
2) Distance = speed times time = 3 * 240 = 720 m
5 0
3 years ago
A simple machine can change the direction of a force.<br> O True<br> O False
tino4ka555 [31]

☁️ Answer ☁️

annyeonghaseyo!

Your answer is:

True.

Several simple machines change the direction of the applied force. These include lever, fulcrum and the pulley.

Hope it helps.

Have a nice day hyung/noona!~  ̄▽ ̄❤️

4 0
2 years ago
Two long parallel wires 40 cm apart are carrying currents of 10 A and 20 A in the opposite direction. What is the magnitude of t
Alex_Xolod [135]

Answer:

The magnitude of the magnetic field halfway between the wires is 3.0 x 10⁻⁵ T.

Explanation:

Given;

distance half way between the parallel wires, r = ¹/₂ (40 cm) = 20 cm = 0.2 m

current carried in opposite direction, I₁ and I₂ = 10 A and 20 A respectively

The magnitude of the magnetic field halfway between the wires can be calculated as;

B = \frac{\mu _oI_1}{2 \pi r} + \frac{\mu_oI_2}{2\pi r}

where;

B is magnitude of the magnetic field halfway between the wires

I₁ is current in the first wire

I₂ is current the second wire

μ₀ is permeability of free space

r is distance half way between the wires

B = \frac{\mu_o I_1}{2\pi r} + \frac{\mu_o I_2}{2\pi r} \\\\B = \frac{\mu_o }{2\pi r} (I_1 +I_2)\\\\B = \frac{4\pi *10^{-7} }{2\pi *0.2} (10 +20) = 3.0 *10^{-5}\  T

Therefore, the magnitude of the magnetic field halfway between the wires is 3.0 x 10⁻⁵ T.

5 0
3 years ago
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