Answer:
Explanation:
The sensor contains an LDR which has a resistance of 10kohlms in daylight and 100kohlms in the dark.
If the resistor in the circuit is 1 megaohlm, the total resistance in daylight and darkness will be 1.01 megaohms and 1.1 megaohlms.
The percentage difference = (1.1-1.01)/1.1*100% = 8.18%
If the resistor in the circuit is 25 kohlm, the total resistance in daylight and darkness will be 35 kohms and 125 kohlms.
The percentage difference = (125-35)/125*100% = 72%
With the input p.d to the sensing circuit fixed at 12 v, the sensing current will change according to the total resistance. A 72% difference is much more detectable. So the 25 kohm resistor is the better choice.
Answer:
<em>The equivalent resistance of the combination is R/100</em>
Explanation:
<u>Electric Resistance</u>
The electric resistance of a wire is directly proportional to its length. If a wire of resistance R is cut into 10 equal parts, then each part has a resistance of R/10.
Parallel connection of resistances: If R1, R2, R3,...., Rn are connected in parallel, the equivalent resistance is calculated as follows:

If we have 10 wires of resistance R/10 each and connect them in parallel, the equivalent resistance is:

This sum is repeated 10 times. Operating each term:

All the terms have the same denominator, thus:

Taking the reciprocals:

The equivalent resistance of the combination is R/100
Answer:
<h2>2.55 Hz</h2>
Explanation:
The frequency of the wave given it's velocity and wavelength can be found by using the formula

where
c is the velocity of the wave in m/s
is the wavelength in m
From the question
c = 7.9 m/s
= 3.1 m
We have

We have the final answer as
<h3>2.55 Hz</h3>
Hope this helps you
Answer:
Potential energy increases.
Explanation:
We know that the direction of electric field is from positive to negative charge. As the proton has the positive charge so if it moves in the direction opposite of electric field, it means that the positive charge will move towards the positive region. As the positive charge is attracted towards negative and repelled by the positive charge. So the work done will be negative in bringing the positive charge towards the positive region of the field and potential energy increases in the direction opposite to electric field. As the potential energy decreases in the direction of electric field.