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Dmitriy789 [7]
3 years ago
5

Find the Gravitational Potential at a point on the earth’s surface. Take mass of earth as 5.98 X 10 24 kg, its radius as 6.38 X

10 6 m and G = 6.67 X 10 – 11 Nm2 kg – 2.

Physics
1 answer:
kherson [118]3 years ago
5 0

Answer:

-6.25 x 10^7 J/Kg\\\\

Explanation:

The final answer is  -6.25 x 10^7 J/Kg\\\\

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The vector, the x-component and the y-component form a rectangle triangle where the vector is the hypothenuse and the x and y components are the two sides.
Calling \alpha the angle between the vector and the horizontal direction (x), the two sides are related to \alpha by
\tan \alpha  =  \frac{v_y}{v_x}
where vy and vx are the two components on the y- and x-axis. Using vx=10 and vy=3 we find
\tan \alpha  =  \frac{3}{10} =0.3
And so the angle is
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3 years ago
A worker pushes a crate horizontally across a warehouse floor with a force of 245 N at an angle of 55 degrees below the horizont
aev [14]

Answer:

option A

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given,

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Movement of crate is due to the horizontal component of the force.

Crate will not move due to vertical force acting on the it.

F_y = F sin \theta

F_y = 245\times sin 55^0

F_y =200.69

hence, worker's force not used to move the crate is equal to 200.69

The correct answer is option A

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3 years ago
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given that

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