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3 years ago

5

Find the Gravitational Potential at a point on the earth’s surface. Take mass of earth as 5.98 X 10 24 kg, its radius as 6.38 X

10 6 m and G = 6.67 X 10 – 11 Nm2 kg – 2.

1 answer:

kherson [118]3 years ago

5 0

Answer:

$-6.25 x 10^7 J/Kg\\\\$

Explanation:

The final answer is $-6.25 x 10^7 J/Kg\\\\$

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Dmitry [639]

Answer:

10.15Ω

Explanation:

From ohm's law,

V = IR...................... Equation 1

Where V = Voltage, I = current, R = resistance.

Assume the voltage across the resistance = V,

Given: I = 6.3 A

Substitute into equation 1

V = 6.3R.................. Equation 2

When an additional resistance of 3.4 Ω is inserted in series with R,

The voltage remain the same, but the current changes

Total Resistance(Rt) = (R+3.4)Ω, I' = 4.72 A

Also from ohm' law,

V = I'Rt............... Equation 3

Substitute the value of I' and Rt into equation 3

V = 4.72(R+3.4)............... Equation 5.

Divide equation 2 by equation 5

V/V = 6.3R/4.72(R+3.4)

1 = 1.335R/(R+3.4)

1 = 1.335R/(R+3.4)

R+3.4 = 1.335R

3.4 = 1.335R-R

3.4 = 0.335R

R = 3.4/0.335

R = 10.15Ω

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Explanation:

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Explanation:

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