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Mashutka [201]
3 years ago
10

What would you use if you needed to determine the density of an object

Chemistry
1 answer:
IrinaVladis [17]3 years ago
8 0
In order to find the density of an object, you need to know the mass of the object and the volume.
That is why the unit of density is kg/m3.
Hope it helps
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Compare a mixture and a compound. How are they alike?
LenKa [72]

Answer:

gnzl8303

gnzl8303vvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvv

Explanation:

8 0
3 years ago
Based on periodic properties, choose the more metallic element from each of the following pairs.
dimulka [17.4K]

Answer:

Sr is the more metallic element

Bi is the more metallic element

O is the more metallic element

As is the more metallic element

Explanation:

One thing should be clear; metallic character increases down the group but decreases across the period.

Hence, as we move across the period, elements become less metallic. As we move down the group elements become more metallic.

This is the basis upon which decisions were made about the metallic character of each of the elements listed above.

7 0
3 years ago
Which has the greatest molecular kinetic energy ? A. Molecules in boiling water B. Molecules in melting ice
xz_007 [3.2K]
It should be C Molecules in falling snow
5 0
3 years ago
Examine the ph scale below. How does household bleach compare to household ammonia?
Kazeer [188]

Answer is: household ammonia has 10 times higher H⁺ concentration.

1) pH(household ammonia) = 11.5.

pH = -log[H⁺], approximately the negative of the base 10 logarithm of the molar concentration of hydrogen ions.

[H⁺] = 10∧(-pH).

[H⁺] = 10∧(-11.5).

[H⁺] = 3.16·10⁻¹² M; concentration of hydrogen ions.

2) pH(household bleach) = 12.5.

[H⁺] = 10∧(-12.5).

[H⁺] = 3.16·10⁻¹³ M.

3) 3.16·10⁻¹² M / 3.16·10⁻¹³ M = 10.

6 0
3 years ago
Read 2 more answers
In an experiment, 16.8 g of k2so4 was dissolved in 1.00 kg of water to make a solution. the freezing point of the solution was m
Mashutka [201]
Answer is: V<span>an't Hoff factor (i) for this solution is 2,26.
</span>Change in freezing point from pure solvent to solution: ΔT =i · Kf · m.
<span>Kf - molal freezing-point depression constant for water is 1,86°C/m.
</span>m -  molality, moles of solute per kilogram of solvent.
n(K₂SO₄) = 16,8 g ÷ 174,25 g/mol
n(K₂SO₄) = 0,096 mol.
m(K₂SO₄) = 0,096 mol/kg.
ΔT = 0,405°C.
i = 0,405 ÷ (1,86 · 0,096)
i = 2,26.

8 0
3 years ago
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