Answer:
I have no idea what that issss
Explanation:
I got B. Because the answer is K2SO4, I got it right on my test so I know its right
PH=-log[H⁺]
pH=-log(1.87×10⁻¹³)
pH=12.72
I hope this helps. Let me know if anything is unclear.
The solution needed is prepared as below
by use of the M1V1 =M2 V2 formula where
M1 = 2.25 L
v2 = 1.0M
M2 = 9.0 M
V2 =? l
make V2 the subject of the formula V2 =M1V1/M2
= 2.25 L x 1.0M/9.0 M = 0. 25 L
therefore the solution need 0.25 L of 9.0M H3PO4 and dilute it a final volume of 2.25 l
