53.5 g MgCl2 /95.21 g/mol = 0.5619 Moles MgCl2. Since the ratio is 3MgCl : 2Na3PO4 you multiply 0.5619 x 2/3 (since you're solving for NaPO, the 2 goes on top) which shows we have .3746 Moles of NaPO. Multiply times it's molar mass so 0.3746x 163.94g/mol= 61.4136 grams NaPO. I believe.
Answer:Use the Law of Sines to solve the triangle ABC if it exists: a) A= 68.41°, B = 54.23”, a = 12.75 ft. b = b = b = a sub ź111347.
Explanation:
Answer:
4.92 grams of sodium phosphate (Na₃PO₄) are required to make 125 milliliters of a 0.240 M.
Explanation:
Molarity is a measure of concentration that indicates the number of moles of solute that are dissolved in a given volume.
The molarity of a solution is calculated by dividing the moles of the solute by the volume of the solution:
Molarity is expressed in units
.
In this case:
- Molarity= 0.240 M
- number of moles= ?
- volume= 125 mL= 0.125 L
Replacing in the definition of molarity:

Solving:
number of moles= 0.240 M*0.125 L
number of moles= 0.03 moles
Being the molar mass of sodium phosphate 164 g/mole, that is, the mass of one mole of the compound, you can calculate the mass of 0.03 moles using the following rule of three: if 1 mole of the compound has 164 grams, 0.03 moles contains how much mass?

mass= 4.92 grams
<u><em>4.92 grams of sodium phosphate (Na₃PO₄) are required to make 125 milliliters of a 0.240 M.</em></u>
Answer:
argon and helium
Explanation:
Argon and Helium is belongs to noble gas. Since novel gases are completely filled outer orbital. therefore they are erratic nature. Hence, noble gas are very stable as it neither except electron nor it denote due to it paired of electronic configuration.
Depending on the materials being welded, these atmospheric gases react with welding area and either it reduces the quality of the weld or make the welding more difficult.
Therefore, to protect welding area from atmospheric gases noble gases which are small in size are used.
Thus, argon and helium are used.