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STALIN [3.7K]
3 years ago
10

the development of cars has pros and cons. the car has allowed for better transportation, but it is also responsible for a great

deal of pollution. which activity can help reduce pollution through the use of new technology? a. building cars that run on nonpolluting fuels b. encouraging people to ride the bus c. building fewer cars d. encouraging people to walk more
Physics
2 answers:
Paha777 [63]3 years ago
8 0

Answer:

A. Building cars that run on nonpolluting fuels.

Explanation:

blondinia [14]3 years ago
3 0

Answer:

A.making an app that allows people top share rides

Explanation:

apesx

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A) A 5.75 mL sample of mercury has a measured mass of 77.05 g. The density is ___________.
Kitty [74]

Answer:

Density of the sample will be 13.4 kg/L

Explanation:

We have given volume of the sample V=5.75mL=5.75\times 10^{-3}L

Mass of the sample M=77.05gram =77.05\times 10^{-3}kg

We have to find the density of the sample

Density of the sample is given by

Density=\frac{mass}{volume}=\frac{77.05\times 10^{-3}}{5.75\times 10^{-3}}=13.4kg/L

So density of the sample will be 13.4 kg/L

4 0
4 years ago
If the force of gravity was suddenly removed between the earth and sun, how would Earth move?
dimaraw [331]

Answer:

the earthe would fly off into space in a straight line

6 0
3 years ago
Why is electricity dead buy solar panels fundamentally different from converting thermal energy into electricity? (Bet you can't
gregori [183]
Because solar panels are man made so they can shut down, not move, break, etc...? Don’t judge me, it’s just a guess.
8 0
3 years ago
What is the energy of the photon that could cause (a) an electronic transition from then= 4 state to the n 5 state of hydrogen a
Fiesta28 [93]

Answer:

a) E_photon =0.306 eV

b) E_photon =0.166 eV

Explanation:

The energy of the photon (E) for n^th orbit of the hydrogen atom is given as:

E_photon = E_o(\frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}})

where,

E_o = 13.6 eV

n = orbit

a) Now for the transition from n = 4 to n = 5

E_photon =13.6(\frac{1}{4^{2}}-\frac{1}{5^{2}})

E_photon =0.306 eV

b) Now for the transition from n = 5 to n = 6

E_photon =13.6(\frac{1}{5^{2}}-\frac{1}{6^{2}})

E_photon =0.166 eV

7 0
3 years ago
A ball is thrown into the air with 100 J of kinetic energy, which is transformed to gravitational potential energy at the top of
masya89 [10]

To solve this problem we could apply the concepts given by the conservation of Energy.

During the launch given in terms of kinetic energy and reaching the maximum point of the object, the potential energy of the body is conserved. However, part of all this energy is lost due to the work done by the friction force due to friction with the air, therefore

E_T = PE + KE -W_f

The potential and kinetic energy are conserved and are the same PE = KE and this value is equivalent to 100J, therefore

E_T = 100-W_f

The kinetic energy will ultimately be less than 100J, so the correct answer is C.

8 0
3 years ago
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