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qaws [65]
3 years ago
10

Gravitational force of attraction “F” exists between two point masses A and B when a fixed distance separates them. After mass A

is tripled and mass B is halved, the gravitational attraction between the two masses is
1/6 F
2/3 F
3/2 F
6 F
Physics
2 answers:
DIA [1.3K]3 years ago
5 0

Answer:

the new gravitational force between the two masses is \frac{3}{2} of the original force (third option in the provided list)

Explanation:

Recall the expression for gravitational force : F_g=G\,\frac{m_A*\,m_B2}{d^2}, where m_A and m_B are the point masses, d the distance between them, and G the universal gravitational constant.

I our problem, the distant between the particles stays unchanged, and we need to know what happens with the magnitude of the force as mass A is tripled, and mass B is halved.

Initial force expression: F_i=G\,\frac{m_A\,m_B}{d^2}

Final force expression: F_f=G\,\frac{3*m_A\,m_B/2}{d^2}\\F_f=G\,\frac{m_A\,m_B\,*\,3/2}{d^2}\\F_f=G\,\frac{m_A\,m_B}{d^2}\,*\frac{3}{2} \\F_f=F_i\,*\frac{3}{2}

Where we have recognized the expression for the initial force between the particles, and replaced it with F_i to make the new relation obvious.

Therefore, the new gravitational force between the two masses is \frac{3}{2} of the original force.

liraira [26]3 years ago
3 0

Answer:

<em>3/2 F is the Answer</em>

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