374u
187u
C₁₄H₂₂N₄O₈
Explanation:
To find the molecular weight of the compound C₁₄H₂₂N₄O₈ we simply sum that atomic masses of the given elements in the compound.
The empirical weight is determined by using the simplest ratio of the elements involved in the compound;
Molecular weight of C₁₄H₂₂N₄O₈;
atomic mass of C = 12g/mol
H = 1g/mol
N = 14g/mol
O = 16g/mol
Molecular weight = 14(12) + 22(1) + 4(14) + 8(16)
= 168 + 22 + 56 + 128
= 374u
Empirical weight:
Empirical formula:
C₁₄ H₂₂ N₄ O₈
14 : 22 : 4 : 8
divide by 2:
7 : 11 : 2 : 4
empirical formula C₇H₁₁N₂O₄
empirical weight = = = 187u
The molecular formula is the actual combination of atoms in a compound. so the molecular formula of the compound is C₁₄H₂₂N₄O₈
learn more:
Molecular mass brainly.com/question/5546238
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Answer:
CuSO4(aq)
Explanation:
The aqueous for of CuSO₄ is an electrolyte and it will conduct electricity.
CuSO₄ is an ionic substance and in solid state, it will not have the ability to conduct electricity.
- In aqueous form, it will contain free mobile ions which serves as carriers of electric current.
- In the solid state, the ions are arranged into a crystal lattice and will not conduct a current of electricity.
- The remaining given compounds will not conduct electricity as they are non-polar and do not have free mobile electrons.
The ideal gas model assumes that gas particles experience no intermolecular attractions.
At low temperature, gas particles move slowly.
At high pressures, gas particles are very close together.
The closeness of the gas particles and their low speed allow intermolecular forces to become important at high pressure and low temperature.
The intermolecular forces cause the gas to deviate from ideal behavior.
Answer:
1.758 x 10⁻¹¹.
Explanation:
∵ pH = - log[H⁺].
∴ 5.47 = -log[H⁺].
log[H⁺] = -5.47.
∴ [H⁺] = 3.388 x 10⁻⁶ M.
∵ [H⁺] = √(Ka.C)
∴ [H⁺]² = Ka.C
<em>∴ Ka = [H⁺]²/C </em>= (3.388 x 10⁻⁶)²(0.653) = <em>1.758 x 10⁻¹¹.</em>
Electrons that have the highest energy are valence electrons. This is because the electron(s) on the outer shell are further away from the attractive force of the nucleus (remember, the nucleus is positively charged as protons are positive and neutrons are neutral, and electrons are negatively charged). This means that electrons on the outer shell are easier to remove, and are more reactive.