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tia_tia [17]
4 years ago
8

A bakery measured the mass of a whole cake as 0.870 kg. A customer bought one slice of the cake and measured the mass of the sli

ce as 0.1151 kg. What is the mass of the remaining cake, without the one slice?
Physics
1 answer:
Brrunno [24]4 years ago
6 0

Answer:

0.7549kg

Explanation:

The mass of the slice + mass of the remaining cake = total mass of cake.

mass of remaining cake = total mass of cake - the mass of the slice

total mass=0.870kg

mass of slice = 0.1151kg

mass of remaining cake = 0.870 - 0.1151

mass of remaining cake=0.7549kg

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Why do we use the name electromagnetism to describe the force of an
ElenaW [278]

Answer:

magnet, gravity

Explanation:

5 0
3 years ago
El coeficiente de variación de la resistencia con la temperatura del carbón es -0.0005/°c.Si la resistencia de una resistencia d
Doss [256]

Answer:

 R (120) = 940Ω

Explanation:

The variation in resistance with temperature is linear in metals

           ΔR (T) = R₀ α ΔT

where α is the coefficient of variation of resistance with temperature, in this case α = -0,0005 / ºC

let's calculate

            ΔR = 1000 (-0,0005) (120-0)

            ΔR = -60 Ω

            ΔR = R (120) + R (0) = -60

            R (120) = -60 + R (0)

            R (120) = -60 + 1000

            R (120) = 940Ω

3 0
3 years ago
An unbalanced force of 500 N is applied to a 75 kg object. What is the acceleration of the object?
NemiM [27]

1. Define Newtons second law of motion (this will help put things into perspective)

2.Get the mass of the object (in this case 75 kg)

3.The net force acting on the object...find it (in this case 500 N)

4.Change the equation to F=ma (500=75a)

5.Divide both sides by 75 and that is the acceleration.

7 0
3 years ago
Read 2 more answers
What is the value of acceleration due to gravity at the pole, equator and the centre of the earth
fgiga [73]

Answer:

In combination, the equatorial bulge and the effects of the surface centrifugal force due to rotation mean that sea-level gravity increases from about 9.780 m/s2 at the Equator to about 9.832 m/s2 at the poles, so an object will weigh approximately 0.5% more at the poles than at the Equator.

7 0
2 years ago
While traveling along a highway a driver slows from 24 m/s to 15 m/s in 12 seconds. What is the automobile's acceleration? (Reme
slava [35]

Answer:

Acceleration = -0.75 m/s²

Explanation:

Given the following data;

Initial velocity = 24 m/s

Final velocity = 15 m/s

Time = 12 seconds

To find the acceleration of the automobile;

Acceleration can be defined as the rate of change of the velocity of an object with respect to time.

This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.

Hence, if we subtract the initial velocity from the final velocity and divide that by the time, we can calculate an object’s acceleration.

Mathematically, acceleration is given by the equation;

Acceleration (a) = \frac {final \; velocity  -  initial \; velocity}{time}

Substituting into the formula, we have;

Acceleration = \frac{15 - 24}{12}

Acceleration = \frac{-9}{12}

Acceleration = -0.75 m/s²

Therefore, the automobile is decelerating because its final velocity is lesser than its initial velocity, leading to a negative value.

5 0
3 years ago
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