First, we're going to see the candies per minute that machine C packs.
150 / 2 = 75
Now that we know that machine C packs 75 candies per minute, we're going to multiply the candies machine C makes by 11 minutes.
75 x 11 = 825
We're now gonna do the same with machine D.
130 x 11 = 1430
Then we're going to find the difference between machine C and machine D, we do this because the question basically asks how much more candies can machine D pack than machine C.
1430 - 825 = 605 candies.
This is how we find our final answer.
Our answer would be D) 605.
Hope this helps!~
Answer:
1. d=m/v
=57.6/112.9
=0.51018601
=0.510g/cm³(3s.f.)
2. m=d×v
=1.8×54
=97.2g
3. v=m/d
=63.8/12.7
=5.02362205
=5.02cm³(3s.f.)
4. v=length×breath×height
=12×2×6
=144m³
216g=0.216kg
d=m/v
=0.216/144
=0.0015kg/m³
Step-by-step explanation:
density=mass/volume
mass=density×volume
volume=mass/density
*make sure the units are correctly placed.
*g/cm³, kg/m³
Answer:
B. The experiment is rolling the die.
C. A trial is one rolling of the die.
F. The outcome is the number that is rolled on the die.
Step-by-step explanation:
An experiment is defined as an act or operation for the purpose of discovering something unknown. In this case the player is rolling the die to discover a number, thus the experiment is rolling the die.
A trial is a single performance of a defined experiment, since we already know what the experiment is, a trial is one rolling of the die.
The outcome is the observed result from a trial or experiment, in this case, the outcome is the number that is rolled on the die.
Answer:
lol
Step-by-step explanation:
If the product of 2 matrices are I this means that B is inverse matrix of A.
the matrix A has been given
if we put symbols for the numbers in matrix A as shown below;
![\left[\begin{array}{ccc}a&b\\c&d\\\end{array}\right] ](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da%26b%5C%5Cc%26d%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%0A)
we need to first find the determinant (D)
D = ad - bc
where a = -1 , b = 4, c = -3 and d = 8
substituting these values
D = -1x8 - (4x-3)
= -8 + 12 = 4
to find the inverse we need to exchange a and d and then multiply both b and c by -1
![\left[\begin{array}{ccc}8&-4\\3&-1\\\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D8%26-4%5C%5C3%26-1%5C%5C%5Cend%7Barray%7D%5Cright%5D%20)
and then have to divide all the terms in matrix by determinant (4)
![\left[\begin{array}{ccc} \frac{8}{4} & \frac{-4}{4} \\ \frac{3}{4} & \frac{-1}{4} \\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%20%5Cfrac%7B8%7D%7B4%7D%20%26%20%5Cfrac%7B-4%7D%7B4%7D%20%5C%5C%20%20%5Cfrac%7B3%7D%7B4%7D%20%26%20%5Cfrac%7B-1%7D%7B4%7D%20%5C%5C%5Cend%7Barray%7D%5Cright%5D)
the simplified inverse matrix B is;
![\left[\begin{array}{ccc} 2 & -1 \\ \frac{3}{4} & \frac{-1}{4} \\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%202%20%26%20-1%20%5C%5C%20%5Cfrac%7B3%7D%7B4%7D%20%26%20%5Cfrac%7B-1%7D%7B4%7D%20%5C%5C%5Cend%7Barray%7D%5Cright%5D)
