The basketball has the greatest gravitational potential energy at its, highest which is at the very top.
Answer:
Explanation:
Given that
Mass of bowling ball M1=7.2kg
The radius of bowling ball r1=0.11m
Mass of billiard ball M2=0.38kg
The radius of the Billiard ball r2=0.028m
Gravitational constant
G=6.67×10^-11Nm²/kg²
The magnitude of their distance apart is given as
r=r1+r2
r=0.028+0.11
r=0.138m
Then, gravitational force is given as
F=GM1M2/r²
F=6.67×10^-11×7.2×0.38/0.138²
F=9.58×10^-9N
The force of attraction between the two balls is
F=9.58×10^-9N
Answer:
Electric force on the charge will be equal to -1742000 N
Explanation:
We have given electric field at a point is E = 260000 N/C
And charge q = -6.7 C
We have to find the force on that charge
Force on the charge is equal to Force = charge × electric field ( multiplication of electric field and charge )
So force will be equal to 
So electric force on the charge will be equal to -1742000 N
Answer:
The right hand rule states that: to determine the direction of the magnetic force on a positive moving charge, ƒ, point the thumb of the right hand in the direction of v, the fingers in the direction of B, and a perpendicular to the palm points in the direction of F.
Explanation:
