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vodomira [7]
3 years ago
8

The diagram below shows a circuit with a

Physics
1 answer:
kirill [66]3 years ago
4 0

Answer:

15v

Explanation:

V = IR

= 0.3*50

= 15V.

I HOPE IT'S HELPFUL

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A 0.750 kg block is attached to a spring with spring constant 13.0 N/m . While the block is sitting at rest, a student hits it w
trapecia [35]

To solve this problem we will apply the concepts related to energy conservation. From this conservation we will find the magnitude of the amplitude. Later for the second part, we will need to find the period, from which it will be possible to obtain the speed of the body.

A) Conservation of Energy,

KE = PE

\frac{1}{2} mv ^2 = \frac{1}{2} k A^2

Here,

m = Mass

v = Velocity

k = Spring constant

A = Amplitude

Rearranging to find the Amplitude we have,

A = \sqrt{\frac{mv^2}{k}}

Replacing,

A = \sqrt{\frac{(0.750)(31*10^{-2})^2}{13}}

A = 0.0744m

(B) For this part we will begin by applying the concept of Period, this in order to find the speed defined in the mass-spring systems.

The Period is defined as

T = 2\pi \sqrt{\frac{m}{k}}

Replacing,

T = 2\pi \sqrt{\frac{0.750}{13}}

T= 1.509s

Now the velocity is described as,

v = \frac{2\pi}{T} * \sqrt{A^2-x^2}

v = \frac{2\pi}{T} * \sqrt{A^2-0.75A^2}

We have all the values, then replacing,

v = \frac{2\pi}{1.509}\sqrt{(0.0744)^2-(0.750(0.0744))^2}

v = 0.2049m/s

7 0
3 years ago
In the diagram, the wavelength is shown by :
MAXImum [283]

Answer:

i think the anwer is C

Explanation:

6 0
3 years ago
an object is tossed upwards with the same inital velocity on the earth then on the moon . will the max
vodomira [7]

The one tossed upward on the Moon will rise to a greater maximum height before starting to fall.  

It'll also spend more total time in flight before returning to the hand that tossed it. (I almost said that it'll spend "more time in the air".  That would be silly on the Moon.)

6 0
3 years ago
What is displacemnet
allsm [11]

Answer:

to move an object from its place or position

Explanation:

if you move an object from where it first was

7 0
3 years ago
Read 2 more answers
180 cm3 of hot tea at 97 °C are poured into a very thin paper cup with 20 g of crushed ice at 0 °C. Calculate the final temperat
Zolol [24]

Answer : The final temperature of the mixture is 91.9^oC

Explanation :

First we have to calculate the mass of water.

Mass = Density × Volume

Density of water = 1.00 g/mL

Mass = 1.00 g/mL × 180 cm³ = 180 g

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of hot water (liquid) = 4.18J/g^oC

c_2 = specific heat of ice (solid)= 2.10J/g^oC

m_1 = mass of hot water = 180 g

m_2 = mass of ice = 20 g

T_f = final temperature of mixture = ?

T_1 = initial temperature of hot water = 97^oC

T_2 = initial temperature of ice = 0^oC

Now put all the given values in the above formula, we get

(180g)\times (4.18J/g^oC)\times (T_f-97)^oC=-(20g)\times 2.10J/g^oC\times (T_f-0)^oC

T_f=91.9^oC

Therefore, the final temperature of the mixture is 91.9^oC

8 0
3 years ago
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