D. 52 km/h
relatve to the track outside. Galiliean relativity
Answer:
T=1.566 N.m
Explanation:
Given that:
rotational speed of the scrank shaft, N = 2500 rpm
power produced by one cylinder, P = 410 W
We know, in case of rotational power:
where: T= torque
Substituting the respective values in the above eq.
T=1.566 N.m is the torque applied by the each piston of the engine.
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