Question

Tĩnh lực tĩnh điện [lực cu lông] giữa 2 điện tích điểm q1,q2 biết q1=2.10-9 q2=4.10-9 r=3cm

Answer 1

• q1=2×10^{-9}C
• q2=4×10^{-9}C
• Radius=3cm=0.3m

Using coulmb's law

$\\ \bull\tt\dashrightarrow F=k\dfrac{q1q2}{r^2}$

$\\ \bull\tt\dashrightarrow F=8.98\dfrac{2\times 10^{-9}\times 4\times 10^{-9}}{(0.3)^2}$

$\\ \bull\tt\dashrightarrow F=8.98\dfrac{8\times 10^{-18}C^2}{0.09m^2}$

$\\ \bull\tt\dashrightarrow F=\dfrac{71.84\times 10^{-18}C^2}{0.09m^2}$

$\\ \bull\tt\dashrightarrow F=798.2\times 10^{18}Nm^2/C^2$

$\\ \bull\tt\dashrightarrow F=7.9\times 10^{16}Nm^2/C^2$