Answer:
80mm or 8cm
Explanation:
According to the lens formula,
1/f = 1/u+1/v
If the object distance u = 4cm = 40mm
Object height = 1.5mm
Image height = 3mm
First, we need to get the image distance (v) using the magnification formula Magnification = image distance/object distance = Image height/object height
v/40=3/1.5
1.5v = 120
v = 120/1.5
v = 80mm
The image distance is 80mm
To get the focal length, we will substitute the image distance and the object distance in the mirror formula to have;
1/f = 1/40+1/-80
Note that the image formed by the lens is an upright image (virtual), therefore the image distance will be negative.
Also the focal length of the converging lens is positive. Our formula will become;
1/f = 1/40-1/80
1/f = 2-1/80
1/f = 1/80
f = 80mm
The focal length of the lens 80mm or 8cm
7,000 decimeters
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Answer:
Part a)
Part B)
since the required static coefficient is more then the given value so it will not remain at rest at highest position.
Part c)
Explanation:
Frictional force on the rock while it is moving upwards along the plane is given as
now we have
now by energy conservation we can say
Work done by friction = loss in mechanical energy
here we know that
Part B)
Now at the maximum height position we can say that force due to static friction must be balanced by its weight along the plane
so we will have
since the required static coefficient is more then the given value so it will not remain at rest at highest position.
Part c)
Again by mechanical energy conservation law
Work done by friction = loss in mechanical energy
here we know that