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lana66690 [7]
3 years ago
7

What is the potential difference VB – VA when the I= 1.5 A in the circuit segment below?​

Physics
1 answer:
son4ous [18]3 years ago
6 0

Answer:

Dahil to sa pilipinas para Hindi I to masakof ng chinaPara lingtas ang mga tao sa pilipinas at is a pa Wang mag kalat sa ebang ebang dumiy

Explanation:

bakit lahat tayo ay ekonomista

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A balloonist drops his camera from a height of 100 m while his balloon is ascending at 5 m/s. How
ExtremeBDS [4]
20 i think is the answer
6 0
3 years ago
Use the drop down menu to complete the sentence. Resistance is measured in units called...
liubo4ka [24]
Ohms is the correct answer
7 0
4 years ago
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7. How much thermal energy is absorbed when 10.0 g of ice at 0.0 degrees C changes phase to liquid water at 0.0 degrees C? The m
Nesterboy [21]

Answer:

3.34 kJ

Explanation:

FIrst of all, we need to calculate the number of moles corresponding to 10.0g of ice. This is given by

n=\frac{m }{M_m}

where

M_m = 18.02 g/mol is the molar mas

m = 10.0 g is the mass

Substituting

n=\frac{m}{M_m}=\frac{10 g}{18.02 g/mol}=0.555 mol

Now we know that the heat of fusion is

H_{fus}=6.01 kJ/mol

so the thermal energy needed to fuse the ice is

Q=n H_{fus} = (0.555 mol)(6.01 kJ/mol)=3.34 kJ

6 0
3 years ago
A point charge of +3 C is located at the origin of a coordinate system and a second point charge of -6 C is at x = 1.0 m. At w
Butoxors [25]

Answer:

The point at which the electrical potential is zero is x = +0.33 m.

Explanation:

By definition the electrical potential is:

V_{E} = \frac{K*q}{r}

Where:

K: is Coulomb's constant = 9x10⁹ N*m²/C²

q: is the charge

r: is the distance

The point at which the electrical potential is zero can be calculated as follows:

V_{1} + V_{2} = 0

K(\frac{q_{1}}{r_{1}} + \frac{q_{2}}{r_{2}}) = 0    (1)

q₁ is the first charge = +3 mC

r₁ is the distance from the point to the first charge  

q₂ is the first charge = -6 mC

r₂ is the distance from the point to the second charge    

By replacing r₁ = 1 - r₂ into equation (1) we have:

K(\frac{q_{1}}{1 - r_{2}} + \frac{q_{2}}{r_{2}}) = 0   (2)

By solving equation (2) for r₂:

r_{2} = \frac{q_{1}}{q_{1} - q_{2}} = \frac{3 mC}{3 mC - (-6 mC)} = +0.33 m

                 

Therefore, the point at which the electrical potential is zero is x = +0.33 m.

I hope it helps you!  

8 0
3 years ago
!Select ALL and ANY that apply!
BaLLatris [955]

Nuclear Reactor is made to use the energy which is released due to nuclear fission reaction.

These chain reactions are very fast and they are used with some components which can control these reactions otherwise these reaction will start with high rate and could not be controlled after that.

In order to control these reactions we need to control the high energy particles which can stimulate these reactions

These are neutrons which act as catalyst of these nuclear reactions and these reactions can be control by controlling the numbers of neutrons

These neutrons can be absorbed by some mechanism and the rods which are used to absorb these high energy neutrons are known as control rods.

So correct answer must be control rods

8 0
4 years ago
Read 2 more answers
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