Answer:
Force of 37.8 × 10^(6) N attracts the two charges
Explanation:
The force between two charges is given by
F = k*q1*q2/r²
Where q1 and q2 are 0.06 C and 0.07 C.
r is the distance between q1 and q2 which is equal to 3 m
k is a constant = 9 × 10^(9) N.m²/C²
F = (9 × 10^(9) × 0.06 × 0.07)/3²
F = 37.8 × 10^(6) N
Answer:
0.2 m
Explanation:
magnetic force = centripetal force
qvB = mv² / r
cancel v on both side and make r subject of the formula
r₁ = mv / qB where m = mass of ion, v = velocity of the ion
r₁ = ( 235 × 1.67 × 10⁻²⁶ × 2.81 × 10⁵) / ( 1.6 × 10⁻¹⁹ × 0.605 T) = 1139.24 × 10⁻² = 11.4 m
r₂ = ( 238 × 1.67 × 10⁻²⁶ × 2.81 × 10⁵) / ( 1.6 × 10⁻¹⁹ × 0.605 T) = 1153.78 × 10⁻² = 11.5 m
D, distance between the impact points formed = d₂ - d₁ where d₂ and d₁ represent the diameters of the charged ions
D = (2 × 11.5 m) - ( 2 × 11.4) = 2 ( 11.5 - 11.4) = 0.2 m
Answer:4.8 m/s^2
Explanation:
mass=10.5kg
Force=50.5N
Acceleration =force ➗ mass
Acceleration =50.5 ➗ 10.5
Acceleration =4.8 m/s^2
Answer:
the one that has more negative sights so the first hand on your right :)
