Answer:
C
Explanation:
looking at a periodic table X is fluorine and Y is potassium
Fluorine is in group 7 and forms a 1- charge (which gains electrons) and potassium is in group 1 and forms a 1+ charge (which loses electrons)
Fluorine (X) has an electronic structure of 2,7 and needs to gain an electron from Potassium (Y) to have a full outer shell and potassium has an electronic structure of 2,8,8,1 so needs to lose an electron to have a full outer shell as well. This means that the electron that potassium (Y) has lost is given away to fluorine (X), so both elements become stable.
This is known as ionic bonding where metals (like potassium) lose electrons and non-metals (like fluorine) gain electrons to become more stable, forming ions
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The correct answer is due to rapid conversion of nitrates into nirites in extracellular fluids.
Due to the fact that it is quickly transformed to nitrates and nitrites in the extracellular fluid, nitric oxide (NO) functions as a paracrine signal that only impacts nearby cells. Because it relaxes the smooth muscle cells in blood vessel walls, nitric oxide (NO) causes blood vessels to widen. Cell signaling is a type of cellular communication in which a cell produces a signal to cause changes in neighboring cells, changing the behavior of those cells. Paracrine signaling is one type of cell signaling. Responses to allergens, tissue repair, the development of scar tissue, and blood clotting are a few examples of paracrine signaling. The transmission of signals through synapses between nerve cells is known as paracrine signaling.
Learn more about paracrine signal here :-
brainly.com/question/12538424
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Answer:
Nitrobenzene is too deactivated (by the nitro group) to undergo a Friedel-Crafts alkylation.
Explanation:
The benzene ring in itself does not easily undergo electrophilic substitution reaction. Some groups activate or deactivate the benzene ring towards electrophilic substitution reactions.
-NO2 ia a highly deactivating substituent therefore, Friedel-Crafts alkylation of nitrobenzene does not take place under any conditions.
This reaction scheme is therefore flawed because Nitrobenzene is too deactivated (by the nitro group) to undergo a Friedel-Crafts alkylation.
