Answer:
Half life is 6 years.
Explanation:
T½ = In2 / λ
Where λ = decay constant.
But N = No * e^-λt
Where N = final mass after a certain period of time
No = initial mass
T = time
N = 0.625g
No = 10g
t = 24 years
N = No* e^-λt
N / No = e^-λt
λ = -( 1 / t) In N / No (inverse of e is In. Check logarithmic rules)
λ = -(1 / 24) * In (0.625/10)
λ = -0.04167 * In(0.0625)
λ = -0.04167 * (-2.77)
λ = 0.1154
T½ = In2 / λ
T½ = 0.693 / 0.1154
T½ = 6.00 years.
The half life of radioactive cobalt-60 is 6 years
Answer:
3.98 C my friend you welcome
Answer:
λ = 1.1×10⁸ m
Explanation:
Given data:
Frequency of wave = 2.7 Hz
Wavelength of wave = ?
Solution:
Formula:
Speed of wave = frequency × wavelength
Speed of wave = 3×10⁸ m/s
now we will put the values in formula.
3×10⁸ m/s = 2.7 s⁻¹ × λ
λ = 3×10⁸ m/s /2.7 s⁻¹
λ = 1.1×10⁸ m
I think this is what you wanted, so good luck!
The table pushes the book and the book pushes the table
It's 3rd law
