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2 years ago

What is the ratio of the volume of the cone to the volume of the cylinder?

Mathematics

2 answers:

makkiz [27]2 years ago

8 0

Answer:

15/16

Step-by-step explanation:

In khan academy, you treat pi as a variable. I just ignore it usually tho.

For the cone you get 15 and for the cylinder you get 16 so 15/16

Alexandra [31]2 years ago

4 0

The ratio of the volume of the cone to the volume of the cylinder is - Ratio Answer =1:2:3

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3 years ago

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Vehicles entering an intersection from the east are equally likely to turn left, turn right, or proceed straight ahead. If 50 ve

ira [324]

Answer:

The probability that at least two-third of vehicles in the sample turn is 0.4207.

Step-by-step explanation:

Let X = number of vehicles that turn left or right.

The proportion of the vehicles that turn is, p = 2/3.

The nest n = 50 vehicles entering this intersection from the east, is observed.

Any vehicle taking a turn is independent of others.

The random variable X follows a Binomial distribution with parameters n = 50 and p = 2/3.

But the sample selected is too large and the probability of success is close to 0.50.

So a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

np ≥ 10
n(1 - p) ≥ 10

Check the conditions as follows:

$np=50\times \frac{2}{3}=33.333>10\\\\n(1-p)=50\times \frac{1}{3}= = 16.667>10$

Thus, a Normal approximation to binomial can be applied.

So, $X\sim N(np, np(1-p))$

Compute the probability that at least two-third of vehicles in the sample turn as follows:

$P(X\geq \frac{2}{3}\times 50)=P(X\geq 33.333)=P(X\geq 34)$

$=P(\frac{X-\mu}{\sigma}>\frac{34-33.333}{\sqrt{50\times \frac{2}{3}\times\frac {1}{3}}})$

$=P(Z>0.20)\\=1-P(Z$

Thus, the probability that at least two-third of vehicles in the sample turn is 0.4207.

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3 years ago