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3 years ago

What keeps the water cycle going?

2 answers:

6 0

The constant use of water flow throwout nature and the way that we use it now isint good and most likly we will be out of water by the year 2055

Mnenie [13.5K]3 years ago

3 0

The water cycle or hydrologic is a continuous cycle where water evaporates, travels into the air and becomes part of a cloud, falls down to earth as precipitation, and then evaporates again. ... Water keeps moving and changing from a solid to a liquid to a gas, over and over again.

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Which is true of electric cars?

lianna [129]

Answer:

they produce no DIRECT emissions

Explanation:

that is why they are good in cities to reduce air pollution . but sometypes can produce lesser emissions.

3 0

2 years ago

How many moles of each element are in one mole of Be(OH)2?

REY [17]

B. 1 mole of beryllium, 2 moles of oxygen, 2 moles of hydrogen

8 0

2 years ago

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Help please. 15.0 moles of gas are in a 3.00L tank at 23.4∘C . Calculate the difference in pressure between methane and an ideal

CaHeK987 [17]

Using PV=nRT or the ideal gas equation, we substitute n= 15.0 moles of gas, V= 3.00L, R equal to 0.0821 L atm/ mol K and T= 296.55 K and get P equal to 121.73 atm. The Van der waals equation is (P + n^2a/V^2)*(V-nb) = nRT. Substituting a=2.300L2⋅atm/mol2 and b=0.0430 L/mol, P is equal to 97.57 atm. The difference is <span>121.73 atm- 97.57 atm equal to 24.16 atm.</span>

3 0

3 years ago

An important reaction that takes place in a blast furnace during the production of iron is the formation of iron metal and CO2 f

ladessa [460]

Answer: Mass of $Fe_2O_3$ required to form 930 kg of iron is 1328 kg

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For iron:

Given mass of iron = 930 kg = 930000 g (1kg=1000g)

Molar mass of iron = 56 g/mol

Putting values in equation 1, we get:

$\text{Moles of iron}=\frac{930000g}{56g/mol}=16607mol$

The chemical equation for the production of iron follows:

$Fe_2O_3+3CO\rightarrow 2Fe+3CO_2$

By Stoichiometry of the reaction:

2 moles of iron are produced by = 1 mole of $Fe_2O_3$

So, 16607 moles of iron will be produced by = $\frac{1}{2}\times 16607=8303moles$ of $Fe_2O_3$

Now, calculating the mass of $Fe_2O_3$ from equation 1, we get:

Mass of $Fe_2O_3$ = $moles\times {\text {molar mass}}=8303\times 160=1328480g=1328kg$

Thus mass of $Fe_2O_3$ required to form 930 kg of iron is 1328 kg

6 0

3 years ago

A 34.0 gram sample of an un-known hydrocarbon is burned in excess oxygen to form 93.5 grams of carbon dioxide and 76.5 grams of

natka813 [3]

Answer:

The answer to your question is CH₄

Explanation:

Process

1.- Write the possible chemical reaction

CxHy + O₂ ⇒ CO₂ + H₂O

2.- Calculate the amount of carbon in the reaction

Molecular mass of CO₂ = 12 + 32 = 44 g

44 g of CO₂ ------------------- 12 g of carbon

93.5 g of CO₂ ---------------- x

x = (93.5 x 12) / 44

x = 25.5 g of carbon

3.- Calculate the mass of hydrogen in the sample

Molecular mass of water = 2 + 16 = 18 g

18 g of water ------------- 2 g of hydrogen

76.5 g of water -------- x g of hydrogen

x = (76.5 x 2) / 18

x = 8.5 g of hydrogen

4.- Calculate the moles of carbon and hydrogen in the sample

12g of carbon ------------- 1 mol

25.5g of carbon ---------- x

x = (25.5 x 1) / 12

x = 2.12 moles of carbon

1 g of hydrogen ----------- 1 mol

8.5 g of hydrogen -------- x

x = (8.5 x 1) / 1

x = 8.5 moles of hydrogen

5.- Divide both number of moles by the lowest number

carbon = 2.12 / 2.12 = 1

hydrogen = 2.12 = 8,5 / 2.12 = 4

6.- Write the molecular formula

CH₄

7 0

2 years ago

Read 2 more answers