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andrezito [222]
2 years ago
13

What are the relevant equations for oxidation and reduction​

Chemistry
2 answers:
Mrac [35]2 years ago
8 0

Explanation:

<u>An oxidation-reduction (redox) reaction is a type of chemical reaction that involves a transfer of electrons between two species. An oxidation-reduction reaction is any chemical reaction in which the oxidation number of a molecule, atom, or ion changes by gaining or losing an electron.</u>

<u>{\large{\red{\mapsto{\maltese{\underline{\green{\boxed{\blue{\underbrace{\overbrace{\pink{\pmb{\bf{Answer࿐by ਪ੍ਰੀਤ:}}}}}}}}}}}}}}</u>

kakasveta [241]2 years ago
7 0

Answer:

There are many equations for oxidation and reduction, but the most relevant ones are the equations for the half-reactions. In general, the equation for oxidation is:

Oxidation: Reducing Agent + O2 → Oxidizing Agent

And the equation for reduction is:

Reduction: Oxidizing Agent + e- → Reducing Agent

These equations show the transfer of electrons that occurs during oxidation and reduction.

Explanation:

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Which objects in space formed from the huge disk of ice and debris beyond the outer planets?
olga_2 [115]
Comets are usually formed of ice and other suave debris, while asteroids typically contain metals.
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4 years ago
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A pharmacy intern is asked to prepare 3 L of a 30% w/v solution. T he pharmacy stocks the active ingredient in 8-ounce bottles o
MariettaO [177]

<u>Answer:</u> The number of bottles that will be needed are 6

<u>Explanation:</u>

We are given:

Amount of solution, the intern is asked to prepare = 3 L = 3000 mL   (Conversion factor:  1 L = 1000 mL)

Strength of solution needed = 30 % (w/v)

This means that in 100 mL of solution, the solute present is 30 grams

So, in 3000 mL of solution, the solute present will be = \frac{30}{100}\times 3000=900g

Active ingredient present in 1 bottle = 8 ounce of 70 % (w/v)

<u>Conversion factor used:</u> 1 ounce = 29.57 mL

So, 8ounce\times \frac{29.57mL}{1ounce}=236.6mL

Amount of active ingredient present in 1 bottle = 236.6\times \frac{70}{100}=165.6g

To calculate the number of bottles, we need to divide the total amount of solution needed by the amount of active ingredient present in 1 bottle, we get:

\text{Number of bottles}=\frac{\text{Amount of solution to prepare}}{\text{Amount of active ingredient in 1 bottle}}

Putting values in above equation, we get:

\text{Number of bottles}=\frac{900g}{165.6g}\\\\\text{Number of bottles}=5.43\approx 6

Hence, the number of bottles that will be needed are 6

6 0
3 years ago
How many micrograms of iron were in the 8.0 mL sample of Greg's blood?
Alenkinab [10]
Answer is: there is 3,36 micrograms of iron in <span>sample of Greg's blood.
</span>m(Fe) = 42 mcg(micrograms).
V(Fe) = 1 dL = 1 dL · 100 mL/1dL.
V(Fe) = 100 mL.
Make proportion: m(Fe) : 8 mL = 42 mcg : 100 mL.
100 mL · m(Fe) = 8 mL · 42 mcg.
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4 0
3 years ago
Calculate the number of moles found in 88.02g of CO2
bija089 [108]

Answer:

2.00moles

Explanation:

mol=mass/mr

88.02/ [12+2(16)] = 2.00

6 0
3 years ago
whats the name of the group 13 of the periodic table? 14 is cristalogens and 15 pnictogens and 16 chalcogens and 17 halogens and
qaws [65]

Answer:

Boron family.

Explanation:

Group 13 is called boron family.

It consist of five members boron, aluminum, gallium, indium and thallium.

Boron is semi metal while other members are metals.

Boron hydrates are used to make organic compounds.

Al is soft metal and aluminum oxides are widely used as thermal insulator.

Aluminum sulfate is also very important commercial compound used in sizing paper.

Gallium is also very important element of this group. It form gallium arsenide which is used to convert the light into electricity.

Indium is malleable soft metal which is used in optical instruments.

Thallium is highly toxic and for the long period of time it as used as insect killing poison.

3 0
3 years ago
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