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andrezito [222]
2 years ago
13

What are the relevant equations for oxidation and reduction​

Chemistry
2 answers:
Mrac [35]2 years ago
8 0

Explanation:

<u>An oxidation-reduction (redox) reaction is a type of chemical reaction that involves a transfer of electrons between two species. An oxidation-reduction reaction is any chemical reaction in which the oxidation number of a molecule, atom, or ion changes by gaining or losing an electron.</u>

<u>{\large{\red{\mapsto{\maltese{\underline{\green{\boxed{\blue{\underbrace{\overbrace{\pink{\pmb{\bf{Answer࿐by ਪ੍ਰੀਤ:}}}}}}}}}}}}}}</u>

kakasveta [241]2 years ago
7 0

Answer:

There are many equations for oxidation and reduction, but the most relevant ones are the equations for the half-reactions. In general, the equation for oxidation is:

Oxidation: Reducing Agent + O2 → Oxidizing Agent

And the equation for reduction is:

Reduction: Oxidizing Agent + e- → Reducing Agent

These equations show the transfer of electrons that occurs during oxidation and reduction.

Explanation:

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Well, it was to capture Japanese controlled islands until the Japanese came into range of the American Bombers, which was different from them going after the Japanese and invading the islands.
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3 years ago
How many moles are in 100g of carbon dioxide?
Fantom [35]

Answer:

A

Explanation:

First, let's find the molar mass of CO₂. This is 12 + 2(16) = 44 g/mole.

Now we can write 100g * (1 mole / 44g) = 2.27 mol, or A. Hope this helps!

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Energy cannot be created or destroyed. Does the statement describe a scientific law?
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3 years ago
Hydrofluoric acid and Water react to form fluoride anion and hydronium cation, like this HF(aq) + H_2O(l) rightarrow F(aq) + H_3
maksim [4K]

Answer:

Kc = 1.09x10⁻⁴

Explanation:

<em>HF = 1.62g</em>

<em>H₂O = 516g</em>

<em>F⁻ = 0.163g</em>

<em>H₃O⁺ = 0.110g</em>

<em />

To solve this question we need to find the moles of each reactant in order to solve the molar concentration of each reactan and replacing in the Kc expression. For the reaction, the Kc is:

Kc = [H₃O⁺] [F⁻] / [HF]

<em>Because Kc is defined as the ratio between concentrations of products over reactants powered to its reaction coefficient. Pure liquids as water are not taken into account in Kc expression:</em>

<em />

[H₃O⁺] = 0.110g * (1mol /19.01g) = 0.00579moles / 5.6L = 1.03x10⁻³M

[F⁻] = 0.163g * (1mol /19.0g) = 0.00858moles / 5.6L = 1.53x10⁻³M

[HF] = 1.62g * (1mol /20g) = 0.081moles / 5.6L = 0.0145M

Kc = [1.03x10⁻³M] [1.53x10⁻³M] / [0.0145M]

<h3>Kc = 1.09x10⁻⁴</h3>
7 0
3 years ago
Which coefficients will balance this equation? *<br> Ag +<br> C2 &gt;<br> AC2
SCORPION-xisa [38]

Answer:

16Ag + 2C2 ---> 4 Ag4C

Explanation:

Ag + C2 ----> AgC2

The valence of Ag is one

Valence of Carbon is four

A balanced equation would be

16Ag + 2C2 ---> 4 Ag4C

7 0
3 years ago
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