I have a small 8==D

Chemistry

2 answers:

barxatty [35]3 years ago

8 0

Its Small And Boring Good Day Sir!!

stich3 [128]3 years ago

3 0

You probably right dude

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Answer : The partial pressure of $H_2O$ is 102.3 mmHg.

Explanation :

As per question,

Mass of $H_2O$ = 62.9 g

Mass of $HOCH_2CH_2OH$ = 33.2 g

Molar mass of $H_2O$ = 18 g/mole

Molar mass of $HOCH_2CH_2OH$ = 62 g/mole

First we have to calculate the moles of $H_2O$ and $HOCH_2CH_2OH$ .

$\text{Moles of }H_2O=\frac{\text{Mass of }H_2O}{\text{Molar mass of }H_2O}=\frac{62.9g}{18g/mole}=3.49mole$

$\text{Moles of }HOCH_2CH_2OH=\frac{\text{Mass of }HOCH_2CH_2OH}{\text{Molar mass of }HOCH_2CH_2OH}=\frac{33.2g}{62g/mole}=0.536mole$

Now we have to calculate the mole fraction of $H_2O$ and $HOCH_2CH_2OH$ .

$\text{Mole fraction of }H_2O=\frac{\text{Moles of }H_2O}{\text{Moles of }H_2O+\text{Moles of }HOCH_2CH_2OH}=\frac{3.49}{3.49+0.536}=0.867$

$\text{Mole fraction of }HOCH_2CH_2OH=\frac{\text{Moles of }HOCH_2CH_2OH}{\text{Moles of }H_2O+\text{Moles of }HOCH_2CH_2OH}=\frac{0.536}{3.49+0.536}=0.134$