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Aliun [14]
3 years ago
9

Group I elements are metals with ................. density

Chemistry
1 answer:
kherson [118]3 years ago
8 0

group 1 elements are metals with<u> low</u> density

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A balloon has a volume of 10,500 liters, and the temperature is 15°C. If the temperature were -25°C, what would the volume of th
harina [27]
Answer is: <span>b) 9,042 L.
Ideal gas law: p</span>·V = n·R·T.
p is the pressure of the gas.
V is the volume of the gas.
n is amount of substance.
R  is universal gas constant.
T is temperature.
T₁ = 15°C = 288 K.
V₁ = 10,5 L.
T₂ = -25°C = 248 K.
V₂ = ?
V₁/T₁ = V₂/T₂
V₂ = 10,5 L · 248 K ÷ 288 K
V₂ = 9,042 L.
8 0
3 years ago
KF + 02 <br><br> Balance the equation
Paladinen [302]

Explanation:

this equation is balanced

if you look at it carefully

k=1

f=1

o=2

we do not have any opposing element

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2 years ago
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9) All elements can be sorted into 3 simple groups:
serious [3.7K]

Answer: B) metals, non-metals, metalloids

An example of a metal is iron. A non-metal example is oxygen, which is a gas at STP (standard temperature and pressure).

A metalloid is a bit of a mix between a metal and non-metal element. It's sorta like an element that has both properties of metals and non-metals, or it's in a murky gray area. An example of a metalloid would be silicon.

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What is the best explanation for why a particle is striking point X?
const2013 [10]

Answer:

What is the best explanation for why a particle is striking point X? When the dense, positive alpha particle passes close to a positive nucleus of gold, the alpha particle repels and hits the screen at point X.

Explanation:

thank me later

8 0
3 years ago
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How many grams of water can be formed from the reaction of 8.76 grams of H2 with 10.5 liters of O2 (at STP) according to the bal
Kisachek [45]

Answer:

16.9g of H₂O can be formed

Explanation:

Based on the chemical reaction, 2 moles of H₂ react per mole of O₂. To anser this question we must find limiting reactant converting the mass and volume of each reactant to moles:

<em>Moles H₂ -Molar mass: 2.016g/mol-:</em>

8.76g * (1mol / 2.016g) = 4.345 moles

<em>Moles O₂:</em>

PV = nRT

PV/RT = n

P = 1atm at STP

V = 10.5L

R = 0.082atmL/molK

T = 273.15K at STP

n = 1atm*10.5L / 0.082atmL/molK*273.15K

n = 0.469 moles of oxygen

For a complete reaction of 4.345 moles moles of hydrogen are required:

4.345 moles H2 * (1mol O2 / 2mol H2) = 2.173 moles of O2 are required. As there are just 0.469 moles, Oxygen is limiting reactant

Now, 1 mole of O2 produce 2 moles of H2O. 0.469 moles will produce:

0.469 moles O₂ * (2 moles H₂O / 1mol O₂) = 0.938 moles H₂O.

The mass is -Molar mas H₂O = 18.01g/mol-:

0.938 moles * (18.01g/mol) =

<h3>16.9g of H₂O can be formed</h3>
8 0
3 years ago
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