Answer:
The net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water and carbon dioxide is -470.4 kJ/mol.
Explanation:
Step 1 : Calcium carbide and water react to form acetylene and calcium hydroxide
..[1]
Step 2 : Acetylene, carbon dioxide and water react to form acrylic acid
..[2]
Using Hess's law:
[1] × 6 + [2]
The energy released on formation of 5 moles of acrylic acid = -2352 kJ
The energy released on formation of 1 moles of acrylic acid :
Hence, the net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water and carbon dioxide is -470.4 kJ/mol.
Its D as A, B and C are physical properties of water
The phase shift in the events is called deposition.
In a vacuum, carbon atoms in gas form a diamond coating on a surface. The conversion of gas phase to solid phase is a part of the described process. As a result, this procedure is known as deposition.
A deposition is a process by which a solid substance is formed from a gaseous one. Bypassing the transitional liquid state, a gaseous substance is deposited in its place (often as crystals). Deposition happens, for instance, when airborne water vapor quickly freezes into ice, as when frost develops.
<h3>
How does deposition occur?</h3>
Whether the eroding agent is gravity, ice, water, waves, or wind, deposition happens when it runs out of energy and can no longer support the burden of the degraded material. Gravity or, in the case of wind, the Sun, provides the energy that the erosion agents can use.
Learn more about deposition: brainly.com/question/12081679
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Answer:
All are correct
Explanation:
1) The angular momentum quantum number, l, are the subshells within a shell (principle quantum number) it talks about the "form" of an orbital, the number itself tells you about the number of angular nodes (a plane without electronic density). It starts at l=0 where you don't see any nodes and it takes the form of an sphere, and we knowing it bu another name an s-orbital. It takes values up to n-1.
l=0 (sphere - s-orbital)
l=1 (p-orbital)
l=2 (d-orbital)
2) The magnetic quatum number, ml relates to the number of orbitals within a subshell then it is related with l, taking values form -l to l incluing 0.
For l=0 (s-orbital) ml=0
For l=1 (p-orbital) ml=1,0,-1
For l=2 (d-orbital) ml=2,1,0,-1,-2
3) In every shell we are restricted by the total number of nodes of any orbital. Then if we want a d-orbital with l=3 we need at least 3 plane nodes only achievable with n=3 at least.
Answer:
Please make it full I'm not seeing it
