Answer:
The specific heat of the alloy
Explanation:
Mass of an alloy = 25 gm
Initial temperature = 100°c = 373 K
Mass of water = 90 gm
Initial temperature of water = 25.32 °c = 298.32 K
Final temperature = 27.18 °c = 300.18 K
From energy balance equation
Heat lost by alloy = Heat gain by water
[
-
] =
(
-
)
25 × × ( 373 - 300.18 ) = 90 × 4.2 (300.18 - 298.32)
This is the specific heat of the alloy.