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Roman55 [17]
3 years ago
11

Two small spherical insulators separated by 2.5 cm, which is much greater than either of their diameters. Both carry positive ch

arge, one +60.0 microCoulombs and the other +6.66 microCoulombs. A third positive charge remains at rest between the two spheres and along the line joining them. What is the position of this charged sphere?
Physics
1 answer:
Zigmanuir [339]3 years ago
5 0

Answer:

1.875 cm from 60 microcoulomb charge.

Explanation:

Let the third charge be Q. Let it be put at x distance from 60 micro coulomb charge for balance.

Force on this charge due to first charge

= \frac{k\times60\times10^{-6}Q}{x^2}

Force on this charge due to second charge

= \frac{k\times6.66\times10^{-6}Q}{(2.5-x)^2}

Since both these forces are equal \frac{k\times60\times10^{-6}Q}{x^2}=\frac{k\times6.66\times10^{-6}Q}{(2.5-x)^2}

\frac{60}{6.66} = \frac{x^2}{(2.5-x)^2}\frac{x}{2.5 -x} = \frac{3}{1}

x = 1.875

1.875 cm from 60 microcoulomb charge.

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