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myrzilka [38]
2 years ago
14

What voltage is measured across the 15 ohm resistor

Physics
1 answer:
Levart [38]2 years ago
6 0
Answer: The voltage across resistor is 75 Volts

A 15-ohm resistor has a 5-A current in it. What is the voltage across the resistor?





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At time t = 1, a particle is located at position (x, y) = (5, 2). If it moves in the velocity field F(x, y) = xy − 1, y2 − 11 fi
Amanda [17]

Answer:

Its approx location is (5.18,1.9)

Explanation:

Using F( 5,2) = ( xy-1, y²-11)

= ( 5*2-¹, 2²-11)

= (9,-5)

= so at point t=1.02

(5,2)+(1.02-1)*(9,-5)

(5,2)+( 0.02)*(9,-5)

(5+0.18, 2-0.1)

= ( 5.18, 1.9)

3 0
3 years ago
If a rock climber accidentally drops a 52.5-g piton from a height of 325 meters, what would its speed be just before striking th
alex41 [277]
Ignoring air resistance, the Kinetic energy before hitting the ground will be equal to the potential energy of the Piton at the top of the rock.  
So we have 1/2 MV^2 = MGH 
V^2 = 2GH 
V = âš2GH 
V = âš( 2 * 9.8 * 325)  
V = âš 6370
 V = 79.81 m/s
6 0
3 years ago
A glass bottle of soda is sealed with a screw cap. The absolute pressure of the carbon dioxide inside the bottle is 1.90 x 105 P
worty [1.4K]

Answer:

The magnitude of the force is 34.59 N.

Explanation:

Given that,

Inside pressure P_{in}= 1.90\times10^{5}\ Pa

Area A=3.90\times10^{-4}\ m^2

Outside pressure = 1 atm

We need to calculate the magnitude of the force

Using formula of force

F_{net}=F_{in}-F_{out}

F_{net}=(P_{in}-P_{out})A

Where, P_{in} =inside Pressure

P_{out} =outside Pressure

A = area

Put the value into the formula

F_{net}=(1.90\times10^{5}-1.013\times10^{5})3.90\times10^{-4}

F_{net}=34.59\ N

Hence, The magnitude of the force is 34.59 N.

6 0
3 years ago
The gravitational force between two objects will be greatest in which of the following situations?
Kobotan [32]

Answer:

Explanation:

Gravitational law states that, the force of attraction or repulsion between two masses is directly proportional to the product of the two masses and inversely proportional to the square of their distance apart.

So,

Let the masses be M1 and M2,

F ∝ M1 × M2

Let the distance apart be R

F ∝ 1 / R²

Combining the two equation

F ∝ M1•M2 / R²

G is the constant of proportional and it is called gravitational constant

F = G•M1•M2 / R²

So, to increase the gravitational force, the masses to the object must be increased and the distance apart must be reduced.

So, option c is correct

C. Both objects have large masses and are close together.

8 0
2 years ago
Macronutrients include carbohydrates, proteins, lipids, and _____.
melamori03 [73]
<span>Macronutrients include carbohydrates, proteins, lipids, and fats.</span>
8 0
3 years ago
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