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2 years ago

11

Find the distance travelled when the initial angular velocity is 3 rad/s, the final angular velocity is 25 rad/s and the time of

motion is 10s

1 answer:

Llana [10]2 years ago

5 0

Answer:

Please find attached pdf

Explanation:

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When the same masses are heated by the same amount, which of the following substances will heat up the slowest?

DochEvi [55]

When the same masses are heated by the same amount copper will heat up the fastest. Copper is a good conductor of heat that is why it easily heats up. Gold is not a good conductor of heat because of its stable properties.

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2 years ago

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A 600kg car is moving at 5 m/s to the right and elastically collided with a stationary 900 kg car. What is the velocity of the 9

11111nata11111 [884]

Answer:

$\mathrm{v}_{2} \text { velocity after the collision is } 3.3 \mathrm{m} / \mathrm{s}$

Explanation:

It says “Momentum before the collision is equal to momentum after the collision.” Elastic Collision formula is applied to calculate the mass or velocity of the elastic bodies.

$m_{1} v_{1}=m_{2} v_{2}$

$\mathrm{m}_{1} \text { and } \mathrm{m}_{2} \text { are masses of the object }$

$\mathrm{v}_{1} \text { velocity before the collision }$

$\mathrm{v}_{2} \text { velocity after the collision }$

$\mathrm{m}_{1}=600 \mathrm{kg}$

$\mathrm{m}_{2}=900 \mathrm{kg}$

$\text { Velocity before the collision } v_{1}=5 \mathrm{m} / \mathrm{s}$

$600 \times 5=900 \times v_{2}$

$3000=900 \times v_{2}$

$\mathrm{v}_{2}=\frac{3000}{900}$

$\mathrm{v}_{2}=3.3 \mathrm{m} / \mathrm{s}$

$\mathrm{v}_{2} \text { velocity after the collision is } 3.3 \mathrm{m} / \mathrm{s}$

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3 years ago

What is a Geographic test

Genrish500 [490]

<em>It's a test on Geography!
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2 years ago

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The depth of the Pacific Ocean in the Mariana Trench is 36,198 ft. What is the gauge pressure at this depth

FinnZ [79.3K]

Answer:

the pressure at the depth is 1.08 × $10^{8}$ Pa

Explanation:

The pressure at the depth is given by,

P = h $\rho$ g

Where, P = pressure at the depth

h = depth of the Pacific Ocean in the Mariana Trench = 36,198 ft = 11033.15 meter

$\rho$ = density of water = 1000 $\frac{kg}{m^{3} }$

g = acceleration due to gravity ≈ 9.8 $\frac{m}{s^{2} }$

P = 11033.15 × 9.8 × 1000

P = 1.08 × $10^{8}$ Pa

Thus, the pressure at the depth is 1.08 × $10^{8}$ Pa

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3 years ago

If the opening to the harbor acts just like a single-slit which diffracts the ocean waves entering it, what is the largest angle

soldi70 [24.7K]

Answer:

The angle that the wave would be $\theta = sin ^{-1}\frac{2 \lambda}{D}$

Explanation:

From the question we are told that the opening to the harbor acts just like a single-slit so a boat in the harbor that at angle equal to the second diffraction minimum would be safe and the on at angle greater than the diffraction first minimum would be slightly affected

The minimum is as a result of destructive interference

And for single-slit this is mathematically represented as

$D sin \ \theta =m \lambda$

where D is the slit with

$\theta$ is the angle relative to the original direction of the wave

m is the order of the minimum j

$\lambda$ is the wavelength

Now since in the question we are told to obtain the largest angle at which the boat would be safe

And the both is safe at the angle equal to the second minimum then

The the angle is evaluated as

$\theta = sin ^{-1}[\frac{m\lambda}{D} ]$

Since for second minimum m= 2

The equation becomes

$\theta = \frac{2 \lambda}{D}$

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2 years ago